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Oxana [17]
3 years ago
14

0.8 - 0.5 ÷ 5 + 0.2 (i know the answer is 0.9. i need to know how to get that. as by what i'm doing i keep getting 0.5. tia)​

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

Yes it's 0.9

Step-by-step explanation:

I got that by putting on my calculator and that's it ...

The calculator gave me the

answer

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X<br> 451<br> 412<br> 451<br> Find the value of x.<br> A. 42<br> 2<br> B. 4<br> C. 43<br> D. 43
marysya [2.9K]

Answer:

B. 4

Step-by-step explanation:

cos(45°) = x/4√2

√2/2 = x/4√2

x = 4√2•√2/2

x = 4

8 0
3 years ago
Use induction to prove: For every integer n &gt; 1, the number n5 - n is a multiple of 5.
nignag [31]

Answer:

we need to prove : for every integer n>1, the number n^{5}-n is a multiple of 5.

1) check divisibility for n=1, f(1)=(1)^{5}-1=0  (divisible)

2) Assume that f(k) is divisible by 5, f(k)=(k)^{5}-k

3) Induction,

f(k+1)=(k+1)^{5}-(k+1)

=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1

=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k

Now, f(k+1)-f(k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k

f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k

Take out the common factor,

f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)      (divisible by 5)

add both the sides by f(k)

f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)

We have proved that difference between f(k+1) and f(k) is divisible by 5.

so, our assumption in step 2 is correct.

Since f(k) is divisible by 5, then f(k+1) must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number n^{5}-n is a multiple of 5.

3 0
3 years ago
To the nearest whole number 16,671 is
Pepsi [2]

Answer:

Step-by-step explanation:

17

5 0
3 years ago
Read 2 more answers
Find the area of each sector.
sergey [27]

Answer:

D. \frac{525\pi}{8} m²

Step-by-step explanation:

Area of the sector = ½*r²∅

Where,

Radius (r) = 15 m

Angle in radians (∅) = \frac{7\pi}{12}

Plug in the values into the equation

Area of sector = \frac{1}{2} * 15^2 * \frac{7\pi}{12}

Area of sector = \frac{1}{2} * 225 * \frac{7\pi}{12}

Area of sector = \frac{1*225*7\pi}{2*12}

Area of sector = \frac{1,575\pi}{24}

Simplify

Area of sector = \frac{525\pi}{8}

5 0
3 years ago
Klein stated before 7:10 meg inlinewhich shows this distance written as a decimal
vfiekz [6]
Since decimals have places in 10 100 and 1000 you need a denominator with those number but since you already have a 10 you take the 7 and add a 0. in front so the answer is 0.7


5 0
4 years ago
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