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Fittoniya [83]
3 years ago
9

What is the height of the cone if its volune is 8,138.88 feet CUBED? Use 3.14 for pi. (Radius of base of cone is 12 ft)

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

h = 54 feet

Step-by-step explanation:

The equation for the volume of a cone is V = \frac{1}{3} × π × r² × h.

You have the volume, which is 8,138.88, and the radius of the base, which is 12.

V = 8,138.88

h = 12

π = 3.14

When you plug everything you know into the equation, you get:

V = \frac{1}{3} × 3.14 × r² × h.

8,138.88 = \frac{1}{3} × 3.14 × (12)² × h

After you multiply everything on the right side, you come out with:

8,138.88 = 150.72 × h

To find h, you can divide each side by 150.72.

8,138.88 ÷ 150.72 = 54 feet!

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Help me with this... ​
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i. 171

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i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

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<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

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