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4 years ago

Please Help Asap

Mathematics

1 answer:

sergejj [24]4 years ago

4 0

Answer:

The correct answer is B) y = 2x - 1

Step-by-step explanation:

To find this, first choose any two data points and find the slope. We'll use points (-2, -3) and (0, 1)

m(slope) = (y2 - y1)/(x2 -x1)

m = (1 - -3)/(0 - -2)

m = 4/2

m = 2

Now we use either point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 1 = 2(x - 0)

y - 1 = 2x

y = 2x + 1

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Two people are driving to work at different constant speeds. The graph below shows the distance traveled over time by driver 1.

Luden [163]

Answer:

5 mph

Step-by-sep explanation:

To find of out the difference between the speed of the two drivers in miles per hour (not in miles per minute), first, calculate the unit rate or speed of driver 1 using the graph, and driver 2 using the table given.

Unit rate/speed = distance travelled/time = y/x.

Speed of Driver 1/unit rate:

The graph shows 1.5 miles (y) is travelled in 2 minutes (x).

Convert the 2 minutes to hour, you will have:

$\frac{2}{60} = \frac{1}{30} hr$

Speed in mph = $\frac{y}{x} = \frac{1.5}{\frac{1}{30}} = 1.5*\frac{30}{1} = 45$

Speed of Driver 1 in mph = 45 mph

Speed of Driver 2/unit rate:

The table shows 2.5 miles (y) is travelled in 3 minutes (x).

Convert the 3 minutes to hour, you will have:

$\frac{3}{60} = \frac{1}{20} hr$

Speed in mph = $\frac{y}{x} = \frac{2.5}{\frac{1}{20}} = 2.5*\frac{20}{1} = 50$

Speed of Driver 2 in mph = 50 mph

Difference between the speed of the two drivers = 50 - 45 = 5 mph

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3 years ago

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Murljashka [212]

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3 years ago

1/9 x 5/4<br> Please make a fraction!

goldenfox [79]

Answer:

5/36

Step-by-step explanation:

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3 years ago

Read 2 more answers

Help me please I give thanks

Ivenika [448]

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3 years ago

If the graph of the function h defined by =hx+−4x23 is translated vertically downward by 9 units, it becomes the graph of a func

KengaRu [80]

Hmmm I can't quite make it the h(x) function, look like $h(x)=4x^{23}$ dunno

however, a vertical transformation or shift of 9 units is just a -9
so hmm notice here
$\qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\mathbb{R}^{{{ B}}x+{{ C}}}+{{ D}}
\end{array}$

$\begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}
\end{array}$

3 0

3 years ago