All categories

2 years ago

У = 2(x + 2)^2+ 10 In standard form

Mathematics

1 answer:

bulgar [2K]2 years ago

7 0

The answer: 2x+y=16

Explanation: calculator

You might be interested in

(x-4)/(2x+1)-3 can you help me with this question

lilavasa [31]

Answer:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

Step-by-step explanation:

Given

$\frac{(x - 4)}{(2x + 1)} - 3$

Required

Solve

Express 3 as a fraction

$\frac{(x - 4)}{(2x + 1)} - \frac{3}{1}$

Take LCM

$\frac{x - 4 - 3(2x + 1)}{3x + 1}$

$\frac{x - 4 - 6x - 3}{3x + 1}$

Collect Like Terms

$\frac{x - 6x- 4 - 3}{3x + 1}$

Simplify like terms

$\frac{-7x- 7}{3x + 1}$

Hence:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

4 0

2 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

2 years ago

Complete the sentence. the midpoint btween 2 and 10 is

kvv77 [185]

Answer:

Step-by-step explanation:

Divide 10 by 2, the result of which is 5, this is the y coordinate of the midpoint

8 0

2 years ago

Read 2 more answers

The pair of points (-4, y) and (5, 7) lie on a line with slope 1/3. What is the value of y? You must show all of your work to re

cestrela7 [59]

Answer:

Step-by-step explanation:

$slope = \frac{y - 7}{ - 4 - 5} = \frac{1}{3}$

y-7=-3, then y=4

8 0

2 years ago

Mark just received word that he scored 88% on a trigonometry test. Mark is also in an advanced algebra course. Is Mark's score o

katen-ka-za [31]

First off, it would not be C because there are no guidelines to score too high on a test
Then, D would also be wrong because since he scored high, it doesn't just mean that the test was easy.
Now it comes to the yes or no between A and B, since he is just one of the many students in Trigonometry, it cant be a very accurate representation therefore the answer to the problem would be A
Solution: A. No, because Mark is not representative of the population of the trigonometry class

4 0

2 years ago