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zlopas [31]
3 years ago
7

mayo runs m miles each day. De'Anthony runs twice as many miles is Mako. Altogether, they run 18 miles each day. How many miles

does Mako run each day.
Mathematics
2 answers:
viva [34]3 years ago
4 0
m+2m=18\implies 3m=18\implies m=6
Alexeev081 [22]3 years ago
4 0

Answer:

6 miles each day.

Step-by-step explanation:

Mako runs m miles each day.

De' Anthony runs twice as many miles as Mako runs = 2m

They run 18 miles each day altogether.

The expression to find the total number of miles does Mako run =

m + 2m = 18

3m = 18

m =  \frac{18}{3}

m = 6 miles

Mako runs 6 miles each day.

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In order to solve the equation -3x-6=5, the first step is to
ss7ja [257]
You will have to get the -3x by itself so you will add 6 to both sides so -3x-6+6-5+6 and you will get -3x=11do you need anymore help?
6 0
3 years ago
Explain why the equations X - 13 = 4 and 13 - X = 4 do NOT have the same solution.
Aloiza [94]

Answer:

they have different answers

Step-by-step explanation:

X - 13 = 4 and 13 - X = 4

for x- 13 = 4

x=4+13=17

x=17

for 13 - x = 4

13-4-x=0

9-x=0

9=x

x=9

6 0
3 years ago
fred can complete a work in 6 days and Paul can complete a work in 3 days. if fred and Paul work together, how many days can the
defon

Answer:

I think its 3 or 2 days bc if paul can get two works done by the time fred can get one done then the days should be divided.

Step-by-step explanation:

3 0
3 years ago
If x = 2, y = 3 and z = 5, calculate the following: 5x - z
nikdorinn [45]
5*2 - 5
5*2=10
10-5=5
5 0
2 years ago
HELP Use either law of sines or law of cosine. Need help on this problem! show work please!​
Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

4 0
3 years ago
Read 2 more answers
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