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Licemer1 [7]
3 years ago
11

Which of the following is an arithmetic sequence?

Mathematics
1 answer:
ira [324]3 years ago
4 0

Answer:

B- because you add 5 eah time

Step-by-step explanation:

You might be interested in
What is the slope of the line whose equation is 2x−4y=10?
Solnce55 [7]

Answer:

1/2

Step-by-step explanation:

-4y = -2x + 10

y = 1/2x - 2/5

The slope is the number in front of the x, so the slope would be 1/2.

6 0
3 years ago
Read 2 more answers
I need to know the answer
Lisa [10]
Slope = rise over run = the change in y over the change of x
if you want it to be exactly 2, then you have to make sure the equations are proportional.
 -5 - y / 6-1
so you simplify it -5-y/ 5
the answer needs to be 2 times 5,
2 x 5 = 10, so you need to add 5 because that's what you subtract from it in the end.
y = 15
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=7x%5E%7B2%7D%20-3%3D60" id="TexFormula1" title="7x^{2} -3=60" alt="7x^{2} -3=60" align="absmid
Pavel [41]

Answer:

<h3>x = -3 , x = 3</h3>

Step-by-step explanation:

7x² - 3 = 60

7x² - 3 - 60 = 0

7x² - 63 = 0

Simplify the terms

Divide both terms by 7

That's

x² - 9 = 0

Solve the quadratic equation

Use difference of two squares

That's

a² - b² = ( a + b)(a - b)

x² - 9 = 0

(x + 3)(x - 3) = 0

x + 3 = 0 x - 3 = 0

x = - 3 x = 3

Hope this helps you

7 0
3 years ago
IM BORD <br> ZOOOOOOOOM <br> AND I NEED HELP IN MATH
Fiesta28 [93]

Answer:

no offense but dont u got friends like call them

Step-by-step explanation:

7 0
3 years ago
The area of two similar triangles are 50dm^2 and 32dm^2. The sum of their perimeters is 117dm. What us the perimeters of each of
Kay [80]

Answer:

Perimeter of one triangle is 65 dm

Perimeter of other triangle is 52 dm

Step-by-step explanation:

Please remember the concept

If sides are in the ratio of a:b

Then the area in the ratio of a^{2} :b^{2}

It is given sum of their perimeter is 117.

Let the small triangle has perimeter as x.

So, perimeter of big triangle is 117-x.

So, we can set up equation as

\frac{50}{32} =\frac{x^{2} }{(117-x)^{2} }

Cross multiply

50(117-x)^2 =32x^2

Expand the left side

50(13689 -234x+x^{2} )=32x^{2}

Distribute the left side

684450-11700x+50x^{2}=32x^{2}

Subtract both sides 32x^{2} and rewrite it 18x^{2} -11700x+684450=0

Solve this quadratic for x.

Divide both sides of the equation by 18 to simplify.

x^{2}-650 x+38025=0

Now, if possible let's factor

Find two integers whose multiplication is 38025 but adds to -650.

-65 and -585 works.

So, we can rewrite it as

(x -65)(x-585) =0

Solve them using zero product property

x=65, x=585

So, x=65 works here.

So, perimeter of one triangle is 65 dm

Perimeter of other triangle is 117-65= 52 dm

5 0
3 years ago
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