Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If
Chuck's rate of travel is 4 mph more than Dana's, at what speed does Chuck travel?
1 answer:
Answer: Chuck's travel at a rate of 52mph
Step-by-step explanation:
For Chuck's trip:
D=RT
104= (R+4)T
T= 104 / (R+4)
For Dana's trip:
96 = RT
T= 96/R
Set both equation for Chuck's and Dana together
104/(R+4) =96/R
Then we cross multiply
96(R+4) = 104R
96R + 384 = 104R
104R - 96R = 384
8R = 384
To get R, divide both side by 8
8R/8 = 384/8
R= 48mph
This means Dana's speed is 48mph
Chuck's speed will be: 48mph+4mph = 52mph
You might be interested in
Answer:
69 times
Step-by-step explanation:
$225 - $221.75 = $3.25
$221.75 - $218.50 = $3.25
... etc
Therefore pattern is 3.25
Need to find how many times $3.25 can be taken from $225
So
$225/$3.25 = 69.2 times
69 times (whole number)
I am pretty sure this is what you do....
q = px + 600
p = 600/q
Tom got $50 and Jane got $60 dollars because If you add 50 to 190, it gives you 240 and 60 + 60 = 120 which is half of 240
34% because...
17/50 times 2= .34= 34%
Answer:
11/54 is n did you want it in decimal form 0.2037 bar on top of 03