Question

Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 4 mph more than Dana's, at what speed does Chuck travel?

Answer 1

Answer: Chuck's travel at a rate of 52mph

Step-by-step explanation:

For Chuck's trip:

D=RT

104= (R+4)T

T= 104 / (R+4)

For Dana's trip:

96 = RT

T= 96/R

Set both equation for Chuck's and Dana together

104/(R+4) =96/R

Then we cross multiply

96(R+4) = 104R

96R + 384 = 104R

104R - 96R = 384

8R = 384

To get R, divide both side by 8

8R/8 = 384/8

R= 48mph

This means Dana's speed is 48mph

Chuck's speed will be: 48mph+4mph = 52mph