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seropon [69]
3 years ago
14

Assignment due soon! Need help

Mathematics
1 answer:
Natali [406]3 years ago
6 0
Answer: 30°

Step by step explanation:
1) Supplementary angles add up to 180°
2) (2x+10)+(5x-40)=180
3) solve for x
4) x=30
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9(2*2+4➗2)= can you show how to get the answer. Which is 54.
Katen [24]
Here I'll Simplify it to show the work.
You need PEMDAS

9(2*2+4÷2)
9(4+4÷2)
9(8÷2)
9(4)
9(4) = 9 × 4 = 36

The Answer is 36.
6 0
3 years ago
Read 2 more answers
Find the volume of a HEMIsphere <br> a radius of 4.
pentagon [3]

Answer:

honestly math is my worst subject but i think its 2 im really srry i think thats wrong tho

Step-by-step explanation:

6 0
3 years ago
PLZ HELP ASAP
zubka84 [21]

Here we go.

1) x/5 - 4h = 35

2) {(6-p)/3}+8

3) This is just 1.4k, since the distance you're trying to find is 1.4 times k feet.

You can include a diagram easily enough. Just draw a baseball diamond and two lines, one connecting first and third base and labeled 1.4k, while the other line, connecting home to third, is labeled k.


Hope that helped!

8 0
3 years ago
Rewrite quadratic equation<br> -×^2+2x-10
Lostsunrise [7]
It has no solution because it is not factorable 
6 0
3 years ago
Read 2 more answers
A 3.00-g copper penny at 25.0°C drops from a height of50.0 m to the ground. (
Gnoma [55]
The potential energy, E, of the penny is given by E=mgh.  The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT.  We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT,   then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass.  The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.
6 0
3 years ago
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