Answer:
0.11069
Step-by-step explanation:
We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.
P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

I hope that works for you!
Answer:
w(C(L))= 0.25 |L - 105|
Step-by-step explanation:
you plug in C(L) into L in w(L)
Using the Pythagoras theorem
(sqrt 117)^2 = x^2 + 6^2
x^2 = sqrt117)^2 + 6^2
x^2 = 117 - 36 = 81
so x = 9 answer
7/11 in decimal form rounded to the nearest thousandth is : 0.636