Answer:
c on edg
Step-by-step explanation:
did same question
Answer:
-3x²-5xeˣ-eˣ
-3eˣx²-11eˣx-6eˣ
Step-by-step explanation:
I'm going to go by the picture and not what you wrote in your title.
To find the derivative of this we have to apply the product rule
(a*b)'=
a'*b+a*b'
We plug in our numbers and get
(-3x²+x-2)'*eˣ+(-3x²+x-2)*eˣ'
Now we can evaluate the derivatives and simplify
(-3x²+x-2)'= -6x+1
eˣ'=eˣ
which means we have
(-6x+1)*eˣ+(-3x²+x-2)*eˣ
Simplify
-6xeˣ+eˣ-3x²eˣ+xeˣ-2eˣ
Combine like terms
-3x²eˣ-5xeˣ-eˣ
Now we just need to find the derivative of this
We can apply the same product rule as we did before
(-3x²eˣ)'
Let's start by factoring out the -3 to get
-3(x²eˣ)'
which is equal to
-3(x²eˣ'+x²'eˣ)
Compute this and get
-3(x²eˣ+2xeˣ)= -3x²eˣ-6xeˣ
Now let's find the derivative of the second part
(-5xeˣ)'
-5(x'eˣ+xeˣ')
-5(eˣ+xeˣ)
-5eˣ-5xeˣ
Which means we have
(-3x²eˣ-6xeˣ)+(-5eˣ-5xeˣ)-eˣ
Combine like terms and get
-3eˣx²-11eˣx-6eˣ
The domain of the function g(x)=l2xl +2 is all real numbers and the range is from (0,∞).
Given g(x)= l2xl +2
First of all we know that modulas gives two values for x<0 and x>=0.
The function g(x) if opened gives two values.
for x>=0 g(x)=2x+2
for x<0 g(x)=-2x+2
because we have not told about the description about x so we can put any value in the function.
So the domain is all real numbers.
Now when we take g(x)=2x+2 for x>=0
putting x=0 we get 2 and rest are positive values so the value of g(x) keeps increasing as we increase the value of x. So here range is [2,∞).
Now take g(x)=-2x+2 for x<0
putting smallest number starting from zero but not 0 we will get a number near to 0 but not zero and because when a negative number multiplies with -2 it becomes positive and increase the value of g(x) so here the range becomes (0,∞).
When we talk about overall range it will be [2,∞) ∪(0,∞)
it will be (0,∞).
Hence the domain of the function g(x) is all real numbers and range is from 0 to infinity.
Learn more about domain and range at brainly.com/question/2264373
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Answer:
C. 8
Step-by-step explanation:
still using the equation a^2 = b^2 = c^2
23.
assuming you mean
first term is n=1, so 1²+3=1+3=4
2nd is n=2 so 2²+3=4+3=7
3rd is n=3 so 3²+3=9+3=12
the first 3 terms are 4,7,12
24.
5th term is 5²+3=25+3=28
10th term is 10²+3=100+3=103
difference is 103-28=75
