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hichkok12 [17]
2 years ago
10

HALP!!! PLEASE!! I PROMISE YOU WILL BE MARKED BRAINLIEST!!!

Mathematics
1 answer:
elixir [45]2 years ago
5 0

The sum of the inverses of the solutions of the quadratic equation is equal to 2.75.

<h3>How to find the solutions of the quadratic equation?</h3>

Here we the quadratic equation:

0 = 5x^2 - 11x + 4

The solutions are given by Bhaskara's formula:

x = \frac{11 \pm \sqrt{(-11)^2 - 4*4*5} }{2*5} \\\\x = \frac{11 \pm \sqrt{41} }{10}\\\\

So the two solutions are:

a = \frac{11 + \sqrt{41} }{10}\\\\\\b =  \frac{11 - \sqrt{41} }{10}

Then we have:

\frac{1}{a} + \frac{1}{b}  = \frac{10}{11 + \sqrt{41} }  + \frac{10}{11 - \sqrt{41} } \\\\= \frac{10*(11 + \sqrt{41} + 11 - \sqrt{41})  }{(11 + \sqrt{41})*(11 - \sqrt{41})} \\\\= \frac{10*(11 + 11 )  }{(11 + \sqrt{41})*(11 - \sqrt{41})}\\\\= \frac{220}{80} = 2.75

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

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What statement is valid….
Nataly_w [17]

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3 0
2 years ago
You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
2 years ago
Area of a kite!!!!!!!!!!!!!!!
Ulleksa [173]

Find the area of each triangle then and them together, so:

1/2(15×8) =60

plus

1/2(15×8) =60

plus

1/2(23×8)=92

plus

1/2(23×8)=92

60+60+92+92=304

304 is the total area.

7 0
3 years ago
Read 2 more answers
What is the value of x2+9x+20 when x could be -5, -3 or -6
ANTONII [103]

Answer:

Step-by-step explanation:

You should use a ^ to indicate an exponent. x^2 is the same as x².

x² + 9x + 20

Replace the x with (-5).

(-5)² + 9(-5) + 20 = 25-45+20 = 0

Then do the same with x = (-3):

(-3)² + 9(-3) + 20 = 9 - 27 + 20 = 2

You can do x = (-6)

3 0
3 years ago
The piper family arrived at the campground at the time shown on the clock. I took the family 2 hours and 15 minutes to get to th
aleksklad [387]

Answer:

As you included no picture, I do not know the time on the clock. We can however, work with assumed figures which you can then relate to your question.

Assuming the time on the clock was 10:45 am, if the family took 2 hours and 15 minutes to get to the camp ground, simply subtract this from 10:45 to find out what time they arrived.

Subtract the 2 hours from 10am:

= 10 - 2

= 8am

Subtract the 15 minutes from 45:

= 45 - 15

= 30

Put that together:

= 8:30 am

<em>They left their house at 8:30 am using this scenario. </em>

8 0
3 years ago
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