Which values of a, b, and c correctly complete the division?

In the diagram below, AC is perpendicular to BD. Find the measure of angle AEB.

Rzqust [24]

Hi there!

The measure of angle AEB is equal to 90 because perpendicular lines create 90 degree angles.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0

3 years ago

In circle O, if LP congruent LK, find the measurement of the major arc PNK. A. 112 B.156 C.224 D.248

klasskru [66]

Sorry here for points

3 0

3 years ago

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members of the wide waters club pay 105 dollars per summer season, plus 9.50 each time they rent a boat. Nonmembers must pay 14.

WITCHER [35]

When handling problems of this nature make sure you setup the equations.
x = number of times they rent a boat.

Members
Cost = 105 + 9.50x
Non members because members don't have to pay the 105 we leave it out.
Cost = 14.75x

so now to determin when cost would be equal we set the two equations = to each other

105 + 9.50x = 14.75x

now solve for x

105 = 5.25x

20 = x

so they would have to rent 20 times to equal each other.

4 0

3 years ago

At a zoo, 3 pandas eat a total of 181 1 2pounds of bamboo shoots each day. The male panda eats 3 times as much as the baby. The

S_A_V [24]

Answer:

6037.2 pounds of bamboo shoots does the female panda eat.

Step-by-step explanation:

Total pandas = 3

Total bamboo shoots eaten = 18112 pounds

Let baby panda eats bamboo = x

Male panda eats bamboo= 3x

Female panda eats bamboo = 2x

So, the equation will become

$x+3x+2x=18112$

Now solving the equation to find value of x

$x+3x+2x=18112\\6x=18112\\x=\frac{18112}{6}\\x=3018.6$

The value of x we get : x=3018.6

So, baby panda eats bamboo shoots = 3018.6 pounds

Male panda eats bamboo shoots = 3x = 3(3018.6) = 9055.8 pounds

Female panda eats bamboo shoots = 2x = 2(3018.6)= 6037.2 pounds

So, 6037.2 pounds of bamboo shoots does the female panda eat.

6 0

3 years ago

Prove the following identity : Sin α . Cos α . Tan α = (1 – Cos α) (1 + Cos α)

Umnica [9.8K]

Let's work on the left side first. And remember that
the tangent is the same as sin/cos.

sin(a) cos(a) tan(a)

Substitute for the tangent:

[ sin(a) cos(a) ] [ sin(a)/cos(a) ]

Cancel the cos(a) from the top and bottom, and you're left with

[ sin(a) ] . . . . . [ sin(a) ] which is [ sin²(a) ] That's the left side.

Now, work on the right side:

[ 1 - cos(a) ] [ 1 + cos(a) ]

Multiply that all out, using FOIL:

[ 1 + cos(a) - cos(a) - cos²(a) ]

= [ 1 - cos²(a) ] That's the right side.

Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.

So, on the right side, you could write [ sin²(a) ] .

Now look back about 9 lines, and compare that to the result we got for the left side .

They look quite similar. In fact, they're identical. And so the identity is proven.

Whew !

4 0

3 years ago

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