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3 years ago

Complete the tasks to subtract the polynomials

Mathematics

1 answer:

Talja [164]3 years ago

5 0

Answer:

The additive inverse of the polynomial being subtracted is -0.612-8+181

Step-by-step explanation:

Given expression : (1.32 +0.412 – 241) – (0.612 + 8 - 181)

Now the polynomial being subtracted : (0.612 + 8 - 181)

Additive inverse : The number in the set of real numbers that when added to a given number will give zero.

So, Additive inverse of 0.612 = -0.612

Additive inverse of 8 = -8

Additive inverse of -181 = 181

So, The additive inverse of polynomial being subtracted : -0.612-8+181

So, Option B is true

Hence the additive inverse of the polynomial being subtracted is -0.612-8+181

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Step-by-step explanation:

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3 years ago

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Answer:

$p_v= 0.01$

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Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

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$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

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3 years ago

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Answer:

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(b) 0.40

Step-by-step explanation:

Mutually-exclusive events are those events which cannot occur together.

Consider that events X and Y are mutually exclusive.

P (X and Y) = 0

Here the two events can be defined as follows:

A = A can fix the busted computer

B = B can fix the busted computer

The information provided are as follows:

P (A) = 0.30

P (B) = 0.40

If A cannot, then there is a chance that her friend B can fix it.

The above statement suggest that the events A and B are mutually exclusive, i.e. if A can fix the computer then B does not have to and if cannot then only B will fix it.

That is, P (A and B) = 0.

(a)

Compute the probability it will be fixed by either A or B as follows:

P (A or B) = P (A) + P (B) - P (A and B)

= 0.30 + 0.40 - 0

= 0.70

Thus, the probability it will be fixed by either A or B is 0.70.

(b)

Compute the probability that if it is fixed it will be fixed by B as follows:

P (not A and B) = P (B) - P (A and B)

= 0.40 - 0

= 0.40

Thus, the probability that if it is fixed it will be fixed by B is 0.40.

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3 years ago