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3 years ago

What happens if you fail just one elective in 7th grade?

Mathematics

2 answers:

Dominik [7]3 years ago

7 0

Answer:

Its not like high school it doesn't really count because colleges really look only at your High School Transcripts.

but if you fail in high school there are ways to make up the credits

topjm [15]3 years ago

3 0

Answer: Honestly middle school grades, especially electives don't matter much. don't worry about it.

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Suppose that the die is rolled twice, rather than once. find the probability of rolling an even number on at least one die. find

puteri [66]

We know P = 1/2

X~B(2, 0.5)
n = 1

2C1 from pascal triangle = 2

P(X=0.5)= 2C1 x 0.5 x 0.5

= 0.5
= 50%

7 0

3 years ago

A loan used for buying a home is called a mortgage. The Fortunato family is borrowing $430,000 to buy a home. They are taking ou

garri49 [273]

Answer:

1,942.91

Step-by-step explanation:

3 0

3 years ago

1.how many ways can 3 boys and 6 girls sit in a row of 4 chairs?

Hoochie [10]

Step-by-step explanation:

first way by sitting 3 person in one chair

3 0

3 years ago

Please help me with this. thank you!

Firlakuza [10]

Answer:

1. y = mx + b

Step-by-step explanation:

y = mx + b

2) to find the y intercept you need to see what cross | ( 8,5)

3) 5 = m(8) = b

4) your slope is negative form the why it pointing

5) in this case your slope is 1/3

6) so now you can do your first step now that you have your (y,x) and slope (your solving for (b)

5 = 1/3 (8) + b

5 = 2.6 + b

5 = 2.6

-2.6

2.4 = b

6 0

2 years ago

Read 2 more answers

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago