I will help, what is your book called?
2x²-3xy-2y²-2x-11y-12
Write -3xy as a difference
2x²+xy-4xy-2y²-2x-11y-12
write -2x as a difference
2x²+xy-4xy-2y²+4x-6x-11y-12
Write -11y as a difference
2x²+xy-4xy-2y²+4x-6x-8y-3y-12
Factor out 2x from the expression
2x×(x-2y-3)+xy-2y²+4x-8y-3y-12
Factor out y from the expression
2x×(x-2y-3)+y×(x-2y-3)+4x-8y-12
Factor out 4 from the expression
2x×(x-2y-3)+y×(x-2y-3)+4(x-2y-3)
Factor out x-2y-3 from the expression
Answer: (x-2y-3)x(2x+y+4)
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Answer:
<h2>The answer is 15cm</h2>
Step-by-step explanation:
Let b be the length of the second parallel side
Area of a trapezium is given by

where
h is the height
a and b are the parallel sides
From the question
Area = 230 cm²
height = 20cm
one of parallel side / a = 8 cm
Substitute the values into the above formula and solve for b
That's

Reduce the fraction with 2
That's

Expand the terms
That's


Divide both sides by 10
We have the final answer as
<h3>b = 15cm</h3>
Hope this helps you
Answer:
60.6°
Step-by-step explanation:
Using trigonometry :
Opposite = Height of shadow = 42 feets
Adjacent = height of flagpole = 23.7 feets
Tan θ = opposite / Adjacent
Tan θ = height of shadow / height of flagpole
Tan θ = 42 / 23.7
Tan θ = 1.7721518
θ = tan^-1(1.7721518)
θ = 60.56
θ = 60.6°