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3 years ago

Anybody body willing to help i have to do 1-3 and 14-17 for all of my hw

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

I will help, what is your book called?

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If 3x + 6 = 18, then x = ?

zaharov [31]

Answer:

X=4

Step-by-step explanation:

$3x + 6 = 18 \\ 3x = 18 - 6 \\ 3x = 12 \\ x = 4$

7 0

3 years ago

What is the reciprocal of 159?

wariber [46]

<h2>Hey there! </h2>

<h2>The Reciprocal of 159 is:</h2>

$\frac{1}{159}$

${where \: 1 \: is \: hidden}$

5 0

3 years ago

Using diagonals from a common vertex, how many triangles could be formed from a hexagon?

Komok [63]

A regular hexagon can be dissected into six equilateral triangles by adding a center point

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2 years ago

Area of circle with diameter 14cm is

Alisiya [41]

Answer:

A≈153.94cm²

Step-by-step explanation:

A=πr2

d=2r

Solving forA

A=1

4πd2=1

4·π·142≈153.93804cm²

4 0

3 years ago

Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)

Katen [24]

Answer:

$\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1$ is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a) = (0,±9) and (0,±c) = (0,±11)

The standard equation of parabola is:

$\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1$

From statement, a = 9

c² = a²+b²

(11)² = (9)²+b²

121-81 = b²

40 = b²

Putting the value of a² and b² in standard equation of parabola, we have

$\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1$ which is the answer.

3 0

3 years ago