Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
8.33333333. You know you can use a calculator.
Answer:
4.24 km
Step-by-step explanation:
The x-component of the displacement after the turn is ...
d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km
Adding this to the displacement before the turn, we have ...
x-component of displacement = 2.83 km + 1.41 km = 4.24 km
Answer:
So, to 1 d.p. 7 is about 23% out of 30. (7 of 30=23%)
Step-by-step explanation:
7/30 x 100 =23.3333333333% or 70/3%.
