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3 years ago

Help me plz i really cant work it out

Mathematics

2 answers:

klemol [59]3 years ago

8 0

Answer:

11 m/s

Step-by-step explanation:

Using v = u + at

where

v = final velocity which we want to find out

u = 3

a = 2

t = 4

v=u+at

v = 3 + 2×4

v =11 m/s

Oxana [17]3 years ago

8 0

So v=?
The starting velocity u, and u=3m/s
The acceleration a is 2m/s^2
And it accelerates for time t=4s
So if we plug it all into the equation
v=(3m/s)+(2m/s^2)(4s)
v= (3m/s)+(8m/s)
v= 11 m/s

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Pls help with this volume wiestion

Zielflug [23.3K]

Answer:

15833.6269741 cm^3.But we can make it 15,833.63 cm^3 rounded to the nearest hundredth.

Step-by-step explanation:

so let’s solve this using the following formula -> $V=\pi r^2h$ .

So if the height is 25 and the radius is 12 them we can plug those numbers into the formula.

$\pi (12)^2(35)$ .

So let’s start by doing 12 squared which is 144 then 144*35 which is 5040.

And now 5040*pi which is 15833.6269741 cm^3.But we can make it 15,833.63 cm^3 rounded to the nearest hundredth.

Id you ant to check if my answer is correct look at the image below.

3 0

3 years ago

What is the value of 6P6? A.1 B.36 C.720 D.46,656

3241004551 [841]

$the\ permutationon:\ \ n\ P\ x= \frac{n!}{(n-x)!} \\ \\6\ P\ 6= \frac{6!}{(6-6)!} = \frac{6!}{0!}= \frac{2\cdot3\cdot4\cdot5\cdot6}{1}=720$

$Ans.\ C$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=4%20%5Cfrac%7B1%7D%7B9%7D%20%20%2B%201%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="4 \

tino4ka555 [31]

Step-by-step explanation:

$\tt{ 1. \: \: 4 \frac{1}{9} + 1 \frac{1}{2}}$

⇢ $\tt{ \frac{37}{9} + \frac{3}{2} }$

⇢ $\tt{ \frac{37 \times 2 + 3 \times 9}{18} }$

⇢ $\tt{ \frac{74 + 27}{18} }$

⇢ $\tt{ \frac{101}{18}}$

⇢ $\boxed{ \tt{5 \frac{11}{18}} }$

---------------------------------------------------------

$\tt{ \: 2. \: \: 4 \frac{1}{2} \div \frac{3}{5}}$

⇢ $\tt{ \frac{9}{2} \times \frac{5}{3}}$

⇢ $\tt{ \frac{9 \times 5}{2 \times 3}}$

⇢ $\tt{ \frac{45}{6}}$

⇢ $\boxed{ \tt{7 \frac{3}{6}} }$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0

3 years ago

In the figure, m<2 = 83, and m<21 = 68. Find the measure of each angle

zhuklara [117]

Answer:

m<1 = 97

m<2 = 83

m<3 = 112

m<4 = 68

m<5 = 112

m<6 = 68

m<7 = 97

m<8 = 83

m<9 = 97

m<10 = 83

m<11 = 112

m<12 = 68

m<13 = 112

m<14 = 68

m<15 = 97

m<16 = 83

Step-by-step explanation:

8 0

3 years ago

An ant crawls at a rate of 2 1/6 ft per minute. At this rate, how long does it take the ant to crawl a distance of 5 1/5 ft? Ent

tangare [24]

For 2 1/6 = 13/6 Ft, ant takes = 1 min.
So, for 1 ft, it takes = 6/13 min.

Now, for 5 1/5 = 26/5 min. it would take = 6/13 * 26/512/5 = 2.4 min

In short, Your Answer would be 2.4 min

Hope this helps!

3 0

3 years ago

Read 2 more answers