here is your answer mate.
in triangle ABC
angle ABC + angleBAC + angleACB = 180 Degrees. (angle sum property of triangle)
90 + 58 + angle ACB = 180 degree.
148 + angle ACB = 180 degree.
angle ACB = 180 - 148
angle ACB = 32 degree
the angle of elevation is 32 degrees
Answer:
The answer is attached as an image.
Step-by-step explanation:
- If we assume that the space is 100% of the population then:
88% have something and 12% have nothing.
So within the 88% there are 10% who have TV, 20% who have Radio and 58% who have both TV and Radio.
Answer:
12 1/4
Step-by-step explanation:
common denominator between 8 and 2 is 4, adding those up will be 12.25 in decimal form or 12 1/4
A scale is a term that refers to the <em>representative fraction</em> for comparing the <u>original</u> length and <u>image</u> length of a given <u>object</u>. It means implies that every 1 unit on the <u>drawing</u> is equal to <u>100</u> units on the <u>park</u>.
A <em>scale</em> is a term that can be referred to as the <em>representative fraction</em> that compares the <u>original</u> length and <u>image</u> length of a given <em>object</em>. Types of <u>scale</u> include enlarged scale, reduced scale, and real scale.
- Enlarged scale is a <u>scale</u> that is used when the <u>size</u> of a given <em>object</em> is to be <em>increased</em>.
- <em>Reduced scale</em> is used when the <u>size</u> of a given <u>object</u> is to be <em>decreased</em>.
- <u>Real scale</u> implies the <em>exact size</em> of a given <u>object</u>.
<u>Scale</u> can be expressed as;
Scale = 
Thus a <em>scale</em> has no unit.
Therefore, the given question <em>implies</em> that every 1 unit on the <u>drawing</u> is equal to 100 units on the <u>original</u> park. Thus it is a <em>reduced scale</em>.
For more clarifications on a scale drawing, visit: brainly.com/question/23209981
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Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.