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dalvyx [7]
3 years ago
7

Determine the solution for the system of equations below.

Mathematics
2 answers:
rusak2 [61]3 years ago
3 0
The answer is (0,0) My dude

Blababa [14]3 years ago
3 0

Answer:

The solution is (0,0)

Step-by-step explanation:

Given system of equations,

y = 4x  ---------- (1)

4x+y = 0 ---------(2),

Substitute the value of y from equation (1) in equation (2),

4x + 4x = 0

⇒ 8x = 0

⇒ x = 0

Again from equation (1),

y = 4(0) = 0

Hence, the solution of the system of the equation is (0,0).

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Show that the line with equation 4y+3x=44 is a tangent to the circle with centre (5,1) and radius 5.
viktelen [127]

When a line is a tangent to a circle then the point of a tangent on a circle is perpendicular and also equal to the radius

So for perpendicular.

                                            P = \frac{ax+by+c}{\sqrt{a^2 + b^2} }

4y + 3x - 44 = 0

So, a = 4

      b = 3

      c = -44

      x = 5

      y = 1

Putting the values in the formula, we get

P = -4.2

Since the radius of the circle 5 is not equal  to P, The line is not a tangent to the circle.

7 0
3 years ago
Solve the quadratic equations below using the factorization method.
liubo4ka [24]

Answer: omg this is hard

Step-by-step explanation:

4 0
3 years ago
The volume of a cylinder is 81 pi in^3 and the height of the cylinder is 1 in. What is the radius of the​ cylinder
ladessa [460]

Answer:

18/20π

Step-by-step explanation:

81π ÷ 1 = 81π

81π ÷2 = 18/20π

You do this because the radius is half of the diameter and you need to get rid of the hight by dividing it from the volume.

7 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
Graph the linear equation <br> y=-5
Naya [18.7K]

Answer:

Answer in the picture: x = 1 | y = -5

Step-by-step explanation:

Not sure if that's the answer you're looking for but I think that's it

3 0
3 years ago
Read 2 more answers
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