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serious [3.7K]
3 years ago
9

IV. Intercepts. Give the intercepts of the following linear equations. 1) 5x + 3y = 8 2) 10x + 6y - 12 = 4 3) 2x – 3y = 5 4) 3x

+ 2y = 1 the giver
Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

1)\frac{8}{3}

2)\frac{8}{3}

3)\frac{-5}{3}

4)2

Step-by-step explanation:

1) 5x + 3y = 8

 3y=8-5x

y=\frac{-5}{8} x+\frac{8}{3}

hence intercept is \frac{8}{3}

2) 10x + 6y - 12 = 4

10x + 6y  = 16

6y=16-10x

y=\frac{-10}{6} x+\frac{16}{6}

hence intercept is \frac{8}{3}

3) 2x – 3y = 5

3y=2x-5

y=\frac{2}{3} x+\frac{-5}{3}

hence intercept is \frac{-5}{3}

4) 3x + 2y = 1

2y=-3x+4

y=\frac{-3}{2} x+\frac{4}{2}

hence intercept is 2

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