Question

IV. Intercepts. Give the intercepts of the following linear equations. 1) 5x + 3y = 8 2) 10x + 6y - 12 = 4 3) 2x – 3y = 5 4) 3x + 2y = 1 the giver

Answer 1

Answer:

1)$\frac{8}{3}$

2)$\frac{8}{3}$

3)$\frac{-5}{3}$

4)2

Step-by-step explanation:

1) 5x + 3y = 8

 3y=8-5x

$y=\frac{-5}{8} x+\frac{8}{3}$

hence intercept is $\frac{8}{3}$

2) 10x + 6y - 12 = 4

10x + 6y  = 16

6y=16-10x

$y=\frac{-10}{6} x+\frac{16}{6}$

hence intercept is $\frac{8}{3}$

3) 2x – 3y = 5

3y=2x-5

$y=\frac{2}{3} x+\frac{-5}{3}$

hence intercept is $\frac{-5}{3}$

4) 3x + 2y = 1

2y=-3x+4

$y=\frac{-3}{2} x+\frac{4}{2}$

hence intercept is 2