Ben would receive £390 while Alex would only receive £130
Your answer is 138.61440
Hope this helps.
9514 1404 393
Answer:
A
Step-by-step explanation:
The Pythagorean triple (8, 15, 17) is often seen in algebra and geometry problems. You recognize it as choice A, so you know that is a right triangle.
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A spreadsheet or graphing calculator can perform the tedium of comparing the sum of squares of the shorter sides to the square of the longer side. The attachment shows a spreadsheet used for that purpose. It identifies the triple (8, 15, 17) as the sides of a right triangle.


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- BCD is an isosceles right triangle , right angled at D
- ABC is an equilateral triangle


❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same





(Isosceles triangle)








