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Ivahew [28]
2 years ago
10

Someone help please

Mathematics
1 answer:
Vlad1618 [11]2 years ago
3 0

Answer:

32

Step-by-step explanation:

ok if it was a normal rectangle =

8 x 6

but the middle part takes 4 from the middle

since there are 2 rectangle

4/2 = 2

since there are lines

6 x 2 = 12 + another 12 since the rectangle on the bottom is the same as the top

24 + ...

6 - 4

2 x 4 = 8

24 + 8 =

32

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It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
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Answer:

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Step-by-step explanation:

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