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2 years ago

Given that p(n)=4n2+4n−6 and q(n)=n2−5n+8, find (p−q)(3).

Mathematics

1 answer:

seropon [69]2 years ago

4 0

Answer:

(p-q) (3) = 40 The anwser is c

Step-by-step explanation:

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4. A toy rocket is fired into the air from the top of a barn. It's height (h) above the ground in

Phantasy [73]

Answer:

A) 25

Step-by-step explanation:

You use x= -b/2a in order to get your maximum so x= -10/ 2(-5) and you get x=1. You plug 1 into the function as h(1)=-5(1)^2 + 10(1)+ 20 which gets you 25

6 0

3 years ago

Describe a pattern you notice when adding the sums of fractions with even denominators as opposed to those with odd denominators

GuDViN [60]

When adding fractions with even denominators, you will not get a whole number, there will be a 1/2. When adding fractions with odd denominators there will be a whole number.

8 0

3 years ago

Read 2 more answers

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26

guajiro [1.7K]

We have

SinC/ c = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A = 27 Sin 71 / 26 = about .982

So°

Sin-1(.982) = A = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92 = 26/sin 71

b = 26sin29.92/sin71 = about 13.72

But A could also be an obtuse angle = 180 - 79.08 = 100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08 = 26/sin71

b = 26sin8.08/sin 71 = 3.865

8 0

3 years ago

Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.

hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.

In ΔLOH

By Pythagoras theorem

$LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2$ → (1)

In ΔKOH,

$KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2$ → (2)

In ΔKHL,

$KL^2=LH^2+KH^2$

Using eq (1) and (2), we get

$KL^2=5^2+OH^2+OH^2+4^2$

$9^2=25+2OH^2+16$

⇒ $2OH^2=81-25-16=40$

⇒ $OH=\sqrt{20}=6.324\sim6.3units.$

Put the above value in eq 2, we get

$KH^2=20+4^2=36$

⇒ KH=6 units.

8 0

3 years ago

Read 2 more answers

A certain microprocessor requires either 2, 3, 4, 8, or 12 machine cycles to perform various operations. Twenty-five percent of

myrzilka [38]

Answer:

The average number of machine cycles per instruction for this microprocessor is 5.8.

Step-by-step explanation:

To find the average number of machine cycles per instruction for this microprocessor, we multiply each number of cycles for it's relative frequency.

We have that:

25% require 2 cycles.

20% require 3 cycles.

17.5% require 4 cycles.

12.5% require 8 cycles.

25% require 12 cycles.

So the average number is:

$M = 0.25*2 + 0.2*3 + 0.175*4 + 0.125*8 + 0.25*12 = 5.8$

3 0

3 years ago