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Mariana [72]
3 years ago
15

Solve the quadratic by factoring 2X²-2X-12=0

Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0
2x^2-2x-12=0\\\\2x^2+4x-6x-12=0\\\\2x(x+2)-6(x+2)=0\\\\(x+2)(2x-6)=0\iff x+2=0\ \vee\ 2x-6=0\\\\x=-2\ \vee\ x=3
kupik [55]3 years ago
3 0
2x^2-2x-12=0\\
2(x^2-x-6)=0\\
2(x^2-3x+2x-6)=0\\
2(x(x-3)+2(x-3))=0\\
2(x+2)(x-3)=0\\
x=-2 \vee x=3
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Answer:

11) Irrational number

12) Integer

13) Communitive property of addition

14) Distributive property of addition and multipacation

15) 26

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Step-by-step explanation:

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3 years ago
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Answer:  C) Find the factors of c that add up to b.

==============================================

Explanation:

If we want to factor something in the form x^2+bx+c, then we look for two numbers that

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-------------

Let's look at a specific example

Consider factoring x^2+5x+6

We need to find two numbers that...

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Through trial and error, you should find the two numbers to be 3 and 2. This means it factors to (x+3)(x+2). The order of the factors doesn't matter.

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