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3 years ago

15

Solve the quadratic by factoring 2X²-2X-12=0

2 answers:

olchik [2.2K]3 years ago

7 0

$2x^2-2x-12=0\\\\2x^2+4x-6x-12=0\\\\2x(x+2)-6(x+2)=0\\\\(x+2)(2x-6)=0\iff x+2=0\ \vee\ 2x-6=0\\\\x=-2\ \vee\ x=3$

kupik [55]3 years ago

3 0

$2x^2-2x-12=0\\
2(x^2-x-6)=0\\
2(x^2-3x+2x-6)=0\\
2(x(x-3)+2(x-3))=0\\
2(x+2)(x-3)=0\\
x=-2 \vee x=3$

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3 years ago

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Trava [24]

Answer:

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Step-by-step explanation:

<u>Operations with Fractions</u>

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3 years ago

Read 2 more answers

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Step-by-step explanation:

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Step-by-step explanation:

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