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3 years ago

Solve the quadratic by factoring 2X²-2X-12=0

Mathematics

2 answers:

olchik [2.2K]3 years ago

7 0

$2x^2-2x-12=0\\\\2x^2+4x-6x-12=0\\\\2x(x+2)-6(x+2)=0\\\\(x+2)(2x-6)=0\iff x+2=0\ \vee\ 2x-6=0\\\\x=-2\ \vee\ x=3$

kupik [55]3 years ago

3 0

$2x^2-2x-12=0\\
2(x^2-x-6)=0\\
2(x^2-3x+2x-6)=0\\
2(x(x-3)+2(x-3))=0\\
2(x+2)(x-3)=0\\
x=-2 \vee x=3$

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3 years ago

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11111nata11111 [884]

Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

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Parenthesis
Exponents
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Division
Addition
Subtraction

Left to Right

Distributive Property

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Step-by-step explanation:

Step 1: Define

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Step 2: Simplify

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2 years ago

chegg evaluate the following integral using trigonometric substitution. dx/square root(x^2-81), x > 9

vesna_86 [32]

Integration will be ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c .

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x = 9 secθ

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Substituting values in ∫ 1 dx / ( $x^{2}$ - 81 ) ,

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= ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c

Hence , the integration will be ln | ( x /9 ) + ( $\sqrt{(x/9)^{2} - 1 }$ ) | + c .

To learn more on integration follow link :

brainly.com/question/20156869

#SPJ4

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