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PolarNik [594]
3 years ago
15

A regular decegom has a perimeter of 150 in and an apothem of ≈ 23.1 in. What is the area of this polygon to the nearest tenth o

f a square foot?
Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

<u>Given</u>:

Given that the perimeter of a regular decagon is 150 inches.

The apothem of a regular decagon is 23.1 inches.

We need to determine the area of the polygon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

A=\frac{1}{2}ap

where a is the apothem and p is the perimeter of the polygon.

Substituting the values, we get;

A=\frac{1}{2}(23.1 \times 150)

Multiplying, we get;

A=\frac{1}{2}(3465)

Dividing, we get;

A=1732.5 \ in^2

Thus, the area of the regular decagon is 1732.5 square inches.

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Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

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2M4 =63

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x=252-214

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Anettt [7]

this can be solve by 3 variable equation

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<span> </span>

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Answer:

Step-by-step explanation:

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so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

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Answer:

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