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2 years ago

Like please help-and show work!

Mathematics

1 answer:

tankabanditka [31]2 years ago

4 0

14+4^2\14-3*4 = 15 your answer is 15

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Help! How Can I Determine the interval in which the function is increasing.

Anuta_ua [19.1K]

Answer:

$(2,\infty)$

Step-by-step explanation:

After x=2, we see that the change in y over the change in x is positive since both variables increase with each other, so $(2,\infty)$ is where the function is increasing.

3 0

1 year ago

PLS HELP ASAP WILL GIVE YOU BRAINLIEST

lbvjy [14]

Answer:

y=5 is the correct answer

Step-by-step explanation:

it would be paralell because the x variable goes across in a straight line

4 0

2 years ago

Read 2 more answers

At the beginning of 2012 Jacobs savings account had 675.20. He deposited 40 each month and earned 66.50 interest for the year. W

mamaluj [8]

I'm going to help
soo soo sos os sos so let me help u

5 0

3 years ago

Y +

Usimov [2.4K]

Question:

What is the common denominator of $y+\frac{y-3}{3}$ in the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

A) $3 y(y-3)$

B) $y(y-3)$

C) $3y$

D) $3$

Answer:

Option D : 3 is the common denominator

Explanation:

It is given that the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

We need to determine the common denominator of $y+\frac{y-3}{3}$ from the complex fraction.

Let us consider the fraction $y+\frac{y-3}{3}$

To find the common denominator, let us take LCM.

Thus, rewriting the above fraction as,

$\frac{y}{1} +\frac{y-3}{3}$$

The LCM can be determined by multiplying the denominators.

Thus, we get,

$1\times3=3$

Thus, the common denominator is 3.

Hence, Option D is the correct answer.

6 0

2 years ago

Please help asap!!!

sp2606 [1]

Answer:

$y=\frac{1}{6} (x+5)^2-4.5$

$y=\frac{-1}{20} (x-10)^2+1$

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3 and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5 and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

$(x+5)^2= 4(1.5) (y+4.5)$

$(x+5)^2= 6(y+4.5)$

divide by 6 on both sides

then subtract 4.5 on both sides

$y=\frac{1}{6} (x+5)^2-4.5$

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4 and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10 and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

$(x-10)^2= 4(-5) (y-1)$

$(x-10)^2= -20(y-1)$

divide by -20 on both sides and add 1 on both sides

$y=\frac{-1}{20} (x-10)^2+1$

8 0

2 years ago