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2 years ago

Compare the rates to find which is greater. 50 envelopes for $2.49 or 90 envelopes for $5.50

1 answer:

5 0

We describe this as cost per envelope which tells you the cost gets divided by the number of envelopes.

$2.49/50 = 0.0498 cents per envelope

$5.50/90 = 0.0611 cents per envelope.

So the 90 for $5.50 costs more per envelope than the 50 for $2.49

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a rocket is 1 mile above thw earth in 30 seconds and 5 miles above the earth in 2.5 minutes what is the rockets rate of change i

Veronika [31]

Rate of Change:

At 1 mile in 30 seconds.
At 5 miles in 2.5 minutes. 2.5 minutes = 2.5*60 = 150 seconds.

Rate of change = Change in height / Change in time

= (h₂-h₁)/(t₂-t₁)

= (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.

   = (1/30) miles per second or 0.0333 miles per second.

To have the answer in miles per minute.

   (1/30) miles per second = (1/30) miles/second.

60 seconds = 1minute
1 second = (1/60) minute.

(1/30) miles/second = (1/30) miles/(1/60)minute
   = (1/30) *60 miles / minute
   =    2 miles per minute.

8 0

3 years ago

A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe

soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 87, thus $\mu = 87$ .
The standard deviation is of 25, thus $\sigma = 25$ .

Item a:

This probability is 1 subtracted by the p-value of Z when X = 60, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 87}{25}$

$Z = -1.08$

$Z = -1.08$ has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the p-value of Z when X = 110, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 87}{25}$

$Z = 0.92$

$Z = 0.92$ has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the p-value of Z when X = 110 subtracted by the p-value of Z when X = 60.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is 1 subtracted by the p-value of Z when X = 125, thus:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 87}{25}$

$Z = 1.52$

$Z = 1.52$ has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0

3 years ago

How does substitution help you to solve systems of equations?

kipiarov [429]

In solving equations, each must have vales of x and y. X is any number and Y is the output of any number. If you substitute x for a number, you can solve the equation for y.

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3 years ago

Module 3 DBA: What key features can be identified from graphs of polynomials of higher-

Anna71 [15]

Ratio

L Guess you bozo

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2 years ago

1. Round off each of the following to the nearest whole number.

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