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xenn [34]
3 years ago
15

The path of a ball kicked from the ground can be modeled by the equation y=−1/5(x−5)(x−20), where x and y are measured in feet.

The x-axis represents the ground. How far does the ball land from where it is kicked?
Mathematics
1 answer:
Helen [10]3 years ago
5 0

Answer:

Step-by-step explanation:

This is already factored for the zeros of the quadratic.  If x - 5 = 0 and x - 20 = 0 then x = 5 and 20.  The ball was kicked 5 feet out and landed at 20 feet down the field.  The difference is 15 feet.  That's how far the ball traveled from its initial position on the ground to its landing place.

So 15 feet from where it was kicked.

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Solve the right triangle​ ABC, with Cequals90degrees. Aequals58.3degrees​, cequals24.8 ft
horsena [70]

m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft

Step-by-step explanation:

If ABC is a right triangle, where the right angle is B, then

  • The hypotenuse of the triangle is b and a , c are its legs
  • sin(A) = \frac{a}{b}
  • sin(C) = \frac{c}{b}
  • b=\sqrt{a^{2}+c^{2}}
  • The sum of the measures of the two acute angles A and C is 90°

∵ ABC is a right triangle

∵ m∠C = 90°

∴ c is the hypotenuse and a , b are its legs

∵ m∠A = 58.3°

- The sum of the two acute angles in the right triangle = 90°

∴ m∠A + m∠B = 90°

- Substitute the measure of angle A

∴ 58.3 + m∠B = 90

- Subtract 58.3 from both sides

∴ m∠B = 31.7°

∵ sin(A) = \frac{a}{c}

∵ c = 24.8 feet

∴ sin(58.3) = \frac{a}{24.8}

- By using cross multiplication

∴ a = (24.8) × sin(58.3)

∴ a = 21.1 ft

∵ sin(B) = \frac{b}{c}

∵ c = 24.8 feet

∴ sin(31.7) = \frac{b}{24.8}

- By using cross multiplication

∴ b = (24.8) × sin(31.7)

∴ b = 13.0 ft

m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft

Learn more:

You can learn more about solving the triangle in brainly.com/question/12985572

#LearnwithBrainly

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