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Alik [6]
2 years ago
15

Solve for x. help me please

Mathematics
2 answers:
fenix001 [56]2 years ago
7 0

Answer: B) 20

Step-by-step explanation: the measurement should add up to 180 so if you add 70+80+10 and then subtract that answer from 180 you get the difference of that which is 20

Marina86 [1]2 years ago
5 0

Answer:

the answer is 20

Step-by-step explanation:

180+180=360

80+70=150

180-150=20

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7 0
3 years ago
Q # 7 please help to solve
Neko [114]
The fourth choice - 5/104.

In one cube, there are 3 even numbers - 2,4,6. For two cubes, the total probability is 36.
   3*3 / 36 = 9/36

For letters, there are five vowels over 26 letters = 5 / 26

Multiply the two probabilities to get the probability of rolling two even numbers and selecting one of the vowels.
   9/36 * 5/26 = 5/104
   
6 0
3 years ago
The cost to purchase x tickets for an amusement park is represented by the equations y-50x+3.75. how much would it cost to purch
emmainna [20.7K]
I'm assuming that subtraction sign is mean to be an equals sign. If that is true than the answer is 403.75. 
4 0
3 years ago
What is a rational number and how do you know?
Andreas93 [3]
A rational number is a number that can be express as the ratio of two integers. A number that cannot be expressed that way is irrational.

8 0
2 years ago
A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
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