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Alik [6]
2 years ago
15

Solve for x. help me please

Mathematics
2 answers:
fenix001 [56]2 years ago
7 0

Answer: B) 20

Step-by-step explanation: the measurement should add up to 180 so if you add 70+80+10 and then subtract that answer from 180 you get the difference of that which is 20

Marina86 [1]2 years ago
5 0

Answer:

the answer is 20

Step-by-step explanation:

180+180=360

80+70=150

180-150=20

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using distance formula you can solve it

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3 years ago
What is -4x+4y=12 in elimination
Alborosie
I might be wrong but don’t you need two equations to do the elimination process?
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If you explain and answer i will give brainly
CaHeK987 [17]

6x - 5y = 3          x1

3x - 8y = -15    x2

===============

6x - 5y = 3

6x - 16y = -30

============= -

11y = 33

y = 3

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2 years ago
Help please<br> n/9 + 2/3 = -2/3
Free_Kalibri [48]

Answer:

n = - 12

Step-by-step explanation:

n/9 + 2/3 = - 2/3

n/9 = - 2/3 - 2/3

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5 0
3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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