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vlada-n [284]
3 years ago
10

Find the solution to the multiplication

Mathematics
2 answers:
siniylev [52]3 years ago
7 0

Answer:

the answer is a

Step-by-step explanation:

lions [1.4K]3 years ago
6 0

Answer: -7299

Step-by-step explanation:Hope this helps:)

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Write the solution of the inequality in set builder notation: 2(3p-11)>=-16
Dima020 [189]
The answer would be 
p≥1

hope this helps :3
8 0
3 years ago
Read 2 more answers
The question is in the picture
Snezhnost [94]

Answer:

my bro from another mo it x=10

7 0
3 years ago
Which quotient matches the description of solving with partial quotients for 240÷15
Illusion [34]

Answer:

C. 16

Step-by-step explanation:

240/15

Step one: 10x15= 150

              240-150= 90  

Partial quotient: 10

Step two: 6x15= 90

                 90-90= 0

Partial quotient: 6

Step 3: 10+6= 16

Answer check: 240/15= 16

3 0
3 years ago
Select the point that is a solution to the system if inequalities yx^2-6
labwork [276]

Answer:

The correct answer is A.

A(0,-2)

Step-by-step explanation:

Method 1

You just have to plot each point on the graph.

The one that falls within the solution region is the correct choice.

From the graph, A(0,-2) falls within the solution region.

See graph

Method 2

If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.

The first inequality is

y\:

If we substitute A(0,-2), we get;

-2\:


-2\:


This statement is true.

The second inequality is

y\:>\:x^2-6

If we substitute A(0,-2), we get;

-2\:>\:(0)^2-6

This gives,

-2\:>\:-6

This statement is also true.



8 0
4 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
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