<span>Volume of the pyramid = (1/3) * base area * height
Base area = 230</span>² = 52,900 m²
<span>Volume of the pyramid = (1/3) * 52,900 * 138 = 2,433,400 m</span>³
Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================




To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>

<u>apply chain rule</u>

<u>Equate the first derivative to zero, that is V'(x) = 0</u>




<u />
<u>maximum volume:</u> <u>when h = 40/3</u>


<u>minimum volume:</u> <u>when h = 0</u>


Answer:
L,KMKOMJIUN8IUJJNUJJMJIKM
Step-by-step explanation:
Answer:
g(t) - h(t) = -2t - 1
Step-by-step explanation:
g(t) - h(t) = t-3-3t+2
= -2t -1