Question

A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 89 km/h. What is the car's centripetal acceleration in m/s^2?

Answer 1

Answer:

The car's centripetal acceleration is 1.22 m/s².

Explanation:

Given that,

Diameter of circular track $d= 1.00\ km=1000\ m$

Radius r = 500 m

Constant speed $v = 89\ km/h = 89\times\dfrac{5}{18}=24.722\ m/s$

The centripetal acceleration is defined as,

$a_{c} = \dfrac{v^2}{r}$

Where, v = tangential velocity

r = radius

Put the value into the formula

$a_{c}=\dfrac{(24.722)^2}{500}$

$a_{c}=1.22\ m/s^2$

Hence, The car's centripetal acceleration is 1.22 m/s².