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notsponge [240]
3 years ago
5

The field found in this problem for a moving charge is the same as the field from a current element of length dl carrying curren

t i provided that the quantity qv is replaced by which quantity?
Physics
1 answer:
Sedaia [141]3 years ago
5 0

The magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.

<h3>Magnetic force on charged particle</h3>

The magnetic force on a charged particle is determined from the product of the magnetic field strength (B), speed of the charge (v) and magnitude of the charge (q).

The magnitude of the force is caculated using the following formula;

F = qvB

<h3>Magnetic force on a current carrying element</h3>

The magnitude of the force is calculated using the following formula,

F = BILsinθ

  • when the angle of inclination = 90 degrees

F = BIL

Where;

  • B is the magnetic field strength
  • I is current
  • L is length of the wire

At equal magnetic force, the magnetic field can be calculated as follows;

B = F/qv = F/IL

Thus, the magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.

Learn more about magnetic force here: brainly.com/question/13277365

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