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notsponge [240]
2 years ago
5

The field found in this problem for a moving charge is the same as the field from a current element of length dl carrying curren

t i provided that the quantity qv is replaced by which quantity?
Physics
1 answer:
Sedaia [141]2 years ago
5 0

The magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.

<h3>Magnetic force on charged particle</h3>

The magnetic force on a charged particle is determined from the product of the magnetic field strength (B), speed of the charge (v) and magnitude of the charge (q).

The magnitude of the force is caculated using the following formula;

F = qvB

<h3>Magnetic force on a current carrying element</h3>

The magnitude of the force is calculated using the following formula,

F = BILsinθ

  • when the angle of inclination = 90 degrees

F = BIL

Where;

  • B is the magnetic field strength
  • I is current
  • L is length of the wire

At equal magnetic force, the magnetic field can be calculated as follows;

B = F/qv = F/IL

Thus, the magnetic field for a moving charge is the same as the magnetic field from a current element of length, dL, carrying current, I, provided that the quantity qv is replaced by 'IL'.

Learn more about magnetic force here: brainly.com/question/13277365

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Steam in a heating system flows through tubes whose outer diameter is 5 cm and whose walls are maintained at a temperature of 13
svet-max [94.6K]

Answer:

5945.27 W per meter of tube length.

Explanation:

Let's assume that:

  • Steady operations exist;
  • The heat transfer coefficient (h) is uniform over the entire fin surfaces;
  • Thermal conductivity (k) is constant;
  • Heat transfer by radiation is negligible.

First, let's calculate the heat transfer (Q) that occurs when there's no fin in the tubes. The heat will be transferred by convection, so let's use Newton's law of cooling:

Q = A*h*(Tb - T∞)

A is the area of the section of the tube,

A = π*D*L, where D is the diameter (5 cm = 0.05 m), and L is the length. The question wants the heat by length, thus, L= 1m.

A = π*0.05*1 = 0.1571 m²

Q = 0.1571*40*(130 - 25)

Q = 659.73 W

Now, when the fin is added, the heat will be transferred by the fin by convection, and between the fin and the tube by convection, thus:

Qfin = nf*Afin*h*(Tb - T∞)

Afin = 2π*(r2² - r1²) + 2π*r2*t

r2 is the outer radius of the fin (3 cm = 0.03 m), r1 is the radius difference of the fin and the tube ( 0.03 - 0.025 = 0.005 m), and t is the thickness ( 0.001 m).

Afin = 0.006 m²

Qfin = 0.97*0.006*40*(130 - 25)

Qfin = 24.44 W

The heat transferred at the space between the fin and the tube will be:

Qspace = Aspace*h*(Tb - T∞)

Aspace = π*D*S, where D is the tube diameter and S is the space between then,

Aspace = π*0.05*0.003 = 0.0005

Qspace = 0.0005*40*(130 - 25) = 1.98 W

The total heat is the sum of them multiplied by the total number of fins,

Qtotal = 250*(24.44 + 1.98) = 6605 W

So, the increase in heat is 6605 - 659.73 = 5945.27 W per meter of tube length.

5 0
3 years ago
If a microwave oven produces electromagnetic waves with a frequency of 2.30 ghz, what is their wavelength?
vovikov84 [41]

Answer: wavelength is 1.30 \times 10^8 nm.

The frequency of the microwave is, f = 2.30 GHz.

To Find frequency use the formula:

c=fλ

Where, c is the speed of electromagnetic wave or light. f is the frequency, and λ is the wavelength of light.

Rearranging, \lambda = \frac{c}{f}

Plug in the values,

\lambdam = \frac{3 \times 10^8 m/s}{2.30 GHz\frac{10^9 Hz}{1 GHz}}=0.130 m\frac{10^9 nm}{1 m} = 1.30 \times 10^8 nm.

5 0
4 years ago
Read 2 more answers
Object A has a mass of 100 grams. Object B has a mass of 150 grams. They are both traveling at the same velocity. What can you c
Scilla [17]
-- Momentum is (mass) x (speed). 
Object B has 1.5 times as much momentum as Object A has.

-- Kinetic energy is (1/2) x (mass) x (speed) . 
Object B has 1.5 times as much kinetic energy as Object A has.

-- If they would both stop long enough to get on the scale,
Object B would weigh 1.5 times as much as Object A does.
8 0
3 years ago
A sinusoidal wave traveling on a string has a period of 0.20 s, a wavelength of 32 cm, and an amplitude of 3 cm. The speed of th
Finger [1]

Answer:

v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

Explanation:

If we have a periodic wave we need to satisfy the following basic relationship:

v = \lambda f

From the last formula we see that the velocity is proportional fo the frequency.

For this case we have the following info given by the problem:

T= 0.2 s, \lambda =32 cm* \frac{1m}{100cm} =0.32 m, A= 3cm*\frac{1m}{100 cm}=0.03 m

We know that the frequency is the reciprocal of the period so we have this formula:

f = \frac{1}{T}

And if we replace we got:

f =\frac{1}{0.2 s}= 5Hz

Now since we have the value for the wavelength we can find the velocity like this:

v = 0.32 m * 5Hz = 1.6 \frac{m}{s}

And if we convert this into cm/s we got:

v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

6 0
3 years ago
A 20 N force is applied to an object causing it to move 10 m. How much work was done on the object? How much energy was needed t
olga2289 [7]

Answer:

Here, force=20N and displacement=10m

Work=Force×Displacement=20N×10m=200Nm

3 0
3 years ago
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