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hram777 [196]
3 years ago
6

in a group of 140 adults, 92 watch tennis, 81 play a sport and 40 do neither. find the probability that an adult chosen at rando

m from those who watch tennis does not play a sport
Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Step-by-step explanation:

27.7%

Step-by-step explanation:

Let's call:

n: the number of adults interviewed

t: number of adults who watch tennis

d: number of adults who practice some sport

x: number of adults who watch tennis and do not practice a sport

The probability that a randomly chosen adult watches tennis and does not play any sports is calculated as follows:

- We calculate the probability that a selected adult will see tennis.

P(t) = 92/140 = 0.657

- We calculate the probability that an adult plays a sport:

P(d) = 81/140 = 0.5786

- We calculate the probability that an adult will see tennis and play some sport (See diagram attached)

P (t ∩ d) = 0.657 (0.5786) = 0.3802

Finally the probability that an adult who sees tennis does not play any sport is:

P(x) = P(t) - P(t ∩ d) = 0.657 - 0.3802

P(x) = 0.277

elena55 [62]3 years ago
8 0
38 of them that watch tennis would not play a sport.
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A simple random sample of size n = 49 is obtained from a population with u = 89 and o = 21.
Furkat [3]

Answer:

a) B. The distribution is approximately normal.

b) 0.0322 = 3.22%

c) 0.0202 = 2.02%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean  and standard deviation , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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Mean and standard deviation:

\mu = 89, \sigma = 21

Sample of 49:

This means that n = 49, s = \frac{21}{\sqrt{49}} = 3

(a) Describe the sampling distribution of x.

By the Central Limit Theorem, approximately normal, and the correct answer is given by option B.

(b) What is P (x > 94.55) ?

This is 1 subtracted by the p-value of Z when X = 94.55, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{94.55 - 89}{3}

Z = 1.85

Z = 1.85 has a p-value of 0.9678.

1 - 0.9678 = 0.0322

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Question c:

This is the p-value of Z when X = 82.85. So

Z = \frac{X - \mu}{s}

Z = \frac{82.85 - 89}{3}

Z = -2.05

Z = -2.05 has a p-value of 0.0202.

So

0.0202 = 2.02%

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The school talent show is 90 minutes long. The average rate of the show is about 10 acts every 30 minute. At this rate, how many
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Answer:

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SECOND PART

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100/4=25

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