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Radda [10]
3 years ago
11

Multiply. (-3) X 8 Enter the answer in the box.

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

If my math is right

is it -24?

Step-by-step explanation:

yan [13]3 years ago
3 0
(-3) x 8 =-24 sorry if it’s wrong
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1.-18(12)<br> 2. -352 + -225
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1.-204.5 2.-557

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8 0
3 years ago
Write a compound interest function to model the following situation. Then, find the balance after the given number of years. $16
VARVARA [1.3K]

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Compute x/y if
Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

{:\implies \quad \sf x+\dfrac{1}{y}=4}

Multiplying both sides by y will lead ;

{:\implies \quad \sf xy+1=4y}

{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}

Now, consider the second equation which is ;

{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}

Multiplying both sides by x will yield

{:\implies \quad \sf xy+1=\dfrac{x}{4}}

{:\implies \quad \sf xy=\dfrac{x}{4}-1}

{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}

As LHS of both equations (i) and (ii) are same, so equating both will yield;

{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}

Multiplying both sides by 4 will yield

{:\implies \quad \sf 16y-4=x-4}

{:\implies \quad \sf 16y=x}

Dividing both sides by y will yield :

{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}

<em>Hence, the required answer is 16</em>

5 0
2 years ago
I need some help! thank you!
Step2247 [10]

Answer:

The 1st,Thrid, Fifth Option

Step-by-step explanation:

The first option is true. We can move the orginal square root function to get g(x).

The second option is false. Function g(x) which equals

\sqrt{x - 3}  - 1

Domain is all real numbers greater than or equal to 3.

The third option is true. Since minimum point we can get is 0 in a square root function. We have a vertical shift so our new minimum point is

0 - 1 =  - 1

We can take the sqr root of 0 so

So all real numbers that are greater than or equal to -1 is true.

The fourth option is false, we need to add 3 instead of subtract 3.

The fifth option is true, we can do that to get back to our original function

7 0
3 years ago
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