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Phoenix [80]
3 years ago
8

What is (2,3) (4,1) (6,2) and (3,5) reflected across the y-axis ?

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0
What are the units they have to be reflected by? here’s a bit of help:

x= up and down units
y= left and right units

i forgot if you add or subtract, but hopefully someone smarter will (:

good luck!
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SOMEONE PLZ HELP ME ASAP
Marizza181 [45]

Answer:

XW = 4 units

Step-by-step explanation:

Given tanf° = \frac{2}{1}, then

tanf° = \frac{opposite}{adjacent} = \frac{YW}{XW} = \frac{8}{XW} = \frac{2}{1} ( cross- multiply )

2XW = 8 ( divide both sides by 2 )

XW = 4

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Factoring 0=6X^2+x-7
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3 years ago
Please help!!
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Please could you explain this step by step I’m really stuck.
allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

  • \frac{5}{x + 3} + \frac4{x + 2} = 2
  • 5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)
  • 5 + \frac{4x + 12}{x + 2} = 2x + 6
  • 5(x + 2) +4x + 12 = (2x + 6)(x + 2)
  • 5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12
  • 9x + 22 = 2x^2 + 10x + 12

Let's make one side equal to 0.

  • 0 = 2x^2 + x - 10

Solve by factoring, and then the zero product property.

  • 0 = 2x^2 + x - 10\\

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, ax^2 + bx + c, think two numbers that equal "ac" and add up to "b".

  • 0 = 2x^2 - 4x + 5x - 10
  • 0 = 2x(x - 2) + 5(x - 2)
  • 0 = (2x + 5)(x - 2)

Using the zero product property, set each factor to 0 and solve for x.

  1. 2x + 5 = 0
    2x = -5
    x = -5/2 = -2.5
  2. x - 2 = 0
    x = 2

The two answers are x = -2.5, and x = 2.

3 0
2 years ago
Read 2 more answers
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