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Alex Ar [27]
3 years ago
9

Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (20, 1), parallel t

o the graph of y = 6x + 6
Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

Slope-intercept form:  y = mx + b  

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they have to have the same slope.

y = 6x + 6    The slope of this line is 6, so the parallel line's slope is also 6.

Now that you know m = 6, substitute/plug it into the equation:

y = mx + b         Plug in 6 for "m" in the equation  

y = 6x + b     To find "b", plug in the point (20, 1) into the equation

1 = 6(20) + b

1 = 120 + b       Subtract 120 on both sides to get "b" by itself

1 - 120 = 120 - 120 + b

-119 = b         Now that you know b = -119, plug it into the equation

y = 6x - 119

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it is the highest point but like its in the middle

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for competition,the cheerleading team,is preparing a dance routine that must last 4 minutes,with a variation of +- 5 seconds. fi
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Ideal timeline of the dance routine = 4 minutes = 4 × 60 seconds = 240 seconds

Variation allowed in the dance routine timeline = +- 5 seconds

Let the timeline of the dance routine be T

⇒ 240 seconds - 5 seconds < T < 240 seconds + 5 seconds

⇒ 235 seconds < T < 245 seconds

⇒ \frac{235}{60} minutes < T < \frac{245}{60} minutes

⇒ 3.92 minutes < T < 4.08 minutes

So the least possible time of the dance routine can be 3.92 minutes (or 235 seconds) and the greatest possible time of the dance routine can be 4.08 minutes (or 245 seconds)

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3 years ago
Use PEMDAS to simplify the expression.<br> 7 715-221<br> 2<br> + 10 - (5 x 23)
Bogdan [553]

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Step-by-step explanation:

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3 years ago
Jane is planting a mixture of flowers. For every ounce of Marigold seeds she uses 2/5 of an ounce of lupine seeds how many ounce
dusya [7]

Answer:

\frac{5}{2} ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.  

We will use proportions to solve our given problem.  

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}

Let us simplify our proportion as shown below:

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

\frac{\text{Marigold seeds}}{1}=\frac{5}{2}

\text{Marigold seeds}}=\frac{5}{2}

Therefore, Jane will use \frac{5}{2} ounces of marigold seeds, if she used one ounce of lupine seeds.

6 0
3 years ago
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