The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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Answer:
Step-by-step explanation:
To solve for s, you need to follow these steps.
First multiply by t both sides of the equation.
We get 
Now we divide by r, both sides of the equation.
Finallly we obtain:
or
First factor (x square -36), the answer will be (x+6)(x-6).
Second, cancel the x .
6x/ (x+6)(x-6)
4x/(6)(-6)
4x/-36
Well the first part is 27 but the second part is adding 60 to 21 which is 81. dont forget that!
Answer:
K = -16/33
Step-by-step explanation:
For a problem like this, it is convenient to write the mixed number as an improper fraction:
-11/8 K = 2/3
Now, multiply the equation by the reciprocal of the coefficient of K.
K = (-8/11)(2/3)
K = -16/33
