Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
The answer to this questuon is 2
Answer:
The period of function is 5 and amplitude is 3.
Step-by-step explanation:
<em>The period of the function is the time interval after which it repeats itself.</em>
It means the time interval after which the same value of graph is attained.
In the above case looking at the peak point at time 5 seconds, the same value is obtained at time 10 seconds.
Thus the time interval is (10 - 5) 5 seconds.
<em>Amplitude is the maximum value attained by the graph in the complete interval.</em>
In the above case, the maximum value attained is 3.
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By simple substitution on the left side and on the right side of the given equation, we have to
For <span>coordinates (-3,-9)
-9</span><span>=−8|-3+3|−9
-9</span><span>=−8|0|−9
</span> -9=−9
Therefore, it is demonstrated that<span> the coordinates of the vertex is
(-3,-9)</span>
