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Cloud [144]
4 years ago
8

*************100 POINTS**************

Chemistry
2 answers:
nata0808 [166]4 years ago
8 0

1. A

2. B

3. A

4. D

5. A

Explanation:

I think that should be correct

Basically what we are trying to do here is see if we are going from molecules to moles or moles to molecules.

We know that avogadro's number is 6.022x10^23 molecules in 1 mol of anything.

So if the questions asks you to convert moles to molecules just multiply it by avogadro's number

If the question asks you to convert molecules to moles just divide by avogadro's number

Ksenya-84 [330]4 years ago
8 0

Answer:

1) <u>1.0 *10^-16 moles</u>

<u>2) 2.2 moles</u>

<u>3) 4.9 * 10^25 molecules</u>

<u>4) 2.47 *10^24  atoms</u>

<u>5) 2.2 *10^23 molecules</u>

Explanation:

How many moles of Ne contain 61,000,000 atoms?

1 mol contains 6.022 * 10^23 atoms OR 6.022 *10^23 atoms = 1 mol

6.1 * 10^7 atoms = (1/ 6.022*10^23) * 6.1 * 10^7 =<u> 1.0 *10^-16 moles</u>

<u />

<u />

How many moles of water contain 1.3 x 10^24 molecules?

1 mol contains 6.022 * 10^23 molecules

(1/6.022*10^23)*1.3*10^24 =<u> 2.2 moles</u>

<u />

<u />

How many molecules of SF6 are in 81 moles?

1 mol contains 6.022 *10^23 molecules

81 moles contain 81 * 6.022*10^23 = <u>4.9 * 10^25 molecules</u>

<u />

<u />

How many atoms of carbon are present in 4.10 moles?

1 mol contains 6.022 * 10^23 molecules

4.10 moles contain 4.10 * 6.022*10^23 = <u>2.47 *10^24  atoms</u>

<u />

<u />

How many molecules of NO2 are in 0.36 moles?

1 mol contains 6.022*10^23 molecules

0.36 moles contain 0.36 * 6.022*10^23 = <u>2.2 *10^23 molecules</u>

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One difference between first- and second-order reactions is that ________. One difference between first- and second-order reacti
lakkis [162]

Answer:

(first choice)

<em>One difference between first- and second-order reactions is that </em><em><u>the half-life of a first-order reaction does not depend on [Ao]; the half-life of a second-order reaction does depend on [Ao].</u></em>

Explanation:

<u>1) First order reactions' model</u>

This is a brief deduction of the first order reactions' half-life

  • Equation: aA +b B → cC + dD
  • rate: r = - d[A]/dt = k[A]
  • Integration:

       - d[A]/[A] = kdt ⇒ - ln { [A]/[Ao] } = kt

  • Half-life:

       t half-life = T

       [A] = (1/2) [Ao] ⇒- ln { [A]/[Ao] } = - ln (1/2) = ln(2) = kT

       ⇒ T = ln(2) / T

  • Conclusion:

        <em>* The half-life of a first order reaction is a constant; it does not depend on the initial concentration of the reactants, it only depend on the rate constant.</em>

<u>2) Second order reaction's model:</u>

This is a brief deduction of the second order reactions' half-life

  • Equation: aA +b B → cC + dD
  • rate: r = - d[A]/dt = k[A]²
  • Integration:

       - d[A]/[A]² = kdt ⇒ 1/[Ao] - 1/[A] = kt

  • Half-life:

       t half-life = T

       [A] = (1/2) [Ao] ⇒ 1 / [Ao] - 1 / {2[Ao]} = 1 / {2[Ao]} = kT

       ⇒ T =   1 / {2k[Ao] }

  • Conclusion:

       <em> * The half-life of a second order reaction depends on the initial concentration and the rate constant.</em>

<u>3) Final conclusion:</u>

We have found that while the half life of a first order reaction is does not depend on the initial concentration, the half-life of a second order reaction does depends on the initial concentration. Hence, the correct answer to the question is:

<em>One difference between first- and second-order reactions is that </em><em><u>the half-life of a first-order reaction does not depend on [Ao]; the half-life of a second-order reaction does depend on [Ao].</u></em>      

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Answer: Auroras

Explanation:

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A solution contains 1 LaTeX: \times\:×10−4 M OH– ions. Calculate the solution pH value, and determine if the solution is acidic,
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Answer:

pH = 10

The solution is basic.

Explanation:

A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.

pOH = -log [OH⁻]

pOH = -log 1 × 10⁻⁴

pOH = 4

We can find the pH of the solution using the following expression.

pH + pOH = 14.00

pH = 14.00 - pOH = 14.00 - 4 = 10

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4 years ago
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Sergeeva-Olga [200]

Answer: Plaster of paris cast

Explanation:

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The main use of calcium sulphate,specifically in hospitals,is plaster of paris cast.The powdered form of CaSO4 can be formed into a moldable paste upon hydration.

4 0
3 years ago
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Answer:

a task that is performed for payment

Explanation:

all of the other answers do not pertain to the question

8 0
3 years ago
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