Answer:
0.03
Explanation:
22.8 g Ba(OH)2 (1 mol Ba (OH)2/ 171.34 g) = 0.133 mol Ba (OH)2
77.2 g H2O (1 mol H2O/18 g) = 4.29 mol H2O
X= molar fraction= mol Ba(OH)2/ mol total
X= 0.133/ (0.133+4.29) = 0.03
Answer:
Heating the liquids and letting one boil away first :)
Explanation:
Answer:
the answer is D i believe. i am not shure but im like 70% sure
Lipids are in a class called fat or lipid solvents.