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lapo4ka [179]
4 years ago
9

A solution contains 1 LaTeX: \times\:×10−4 M OH– ions. Calculate the solution pH value, and determine if the solution is acidic,

basic, or neutral. Helpful math formulas: LaTeX: pH=-\log\left[H_3O^+\right]p H = − log ⁡ [ H 3 O + ] LaTeX: pOH=-\log\left[OH^-\right]p O H = − log ⁡ [ O H − ] LaTeX: pH+pOH=14.00p H + p O H = 14.00 LaTeX: \left[H_3O^+\right]\left[OH^-\right]=1.0\times10^{-14}1) The pH of the solution is .Enter your answer with 2 significant figures.
2) The solution is .Enter acidic, basic, or neutral.
Chemistry
1 answer:
docker41 [41]4 years ago
5 0

Answer:

pH = 10

The solution is basic.

Explanation:

A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.

pOH = -log [OH⁻]

pOH = -log 1 × 10⁻⁴

pOH = 4

We can find the pH of the solution using the following expression.

pH + pOH = 14.00

pH = 14.00 - pOH = 14.00 - 4 = 10

Since the pH > 7, the solution is basic.

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The reaction          3 BrO- (aq) --> BrO3- (aq) + 2 Br - (aq) in basic solution is second order in BrO-(aq) with a rate cons
Phoenix [80]

Answer:

0.124 M

Explanation:

The reaction obeys second-order kinetics:

r = k[BrO^-]^2

According to the integrated second-order rate law, we may rewrite the rate law in terms of:

\dfrac{1}{[BrO^-]_t} = kt + \dfrac{1}{[BrO^-]_o}

Here:

k is a rate constant,

[BrO^-]_t is the molarity of the reactant at time t,

[BrO^-]_o is the initial molarity of the reactant.

Converting the time into seconds (since the rate constant has seconds in its units), we obtain:

t = 1.00 min = 60.0 s

Rearranging the integrated equation for the amount at time t:

[BrO^-]_t = \dfrac{1}{kt + \dfrac{1}{[BrO^-]_o}}

We may now substitute the data:

[BrO^-]_t = \dfrac{1}{0.056 M^{-1}s^{-1}\cdot 60.0 s + \dfrac{1}{0.212 M}} = 0.124 M

7 0
3 years ago
The pressure on 150 mL of a gas is increased from 500 mm Hg to 700 mm Hg at constant temperature. What is the new volume of the
Ivanshal [37]

Answer:

Option A. 107 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 150 mL

Initial pressure (P₁) = 500 mmHg

Final pressure (P₂) = 700 mmHg

Temperature = constant

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

500 × 150 = 700 × V₂

75000 = 700 × V₂

Divide both side by 700

V₂ = 75000 / 700

V₂ = 107 mL

Therefore, the final volume of the gas is 107 mL.

4 0
3 years ago
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My name is Ann [436]
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6 0
3 years ago
The pH of the ocean is 8.1. What is the concentration of hydronium ions?
skad [1K]

Answer:

7.9 × 10⁻⁹ M

Explanation:

Step 1: Given data

pH of the ocean: 8.1

Step 2: Calculate the concentration of hydronium ions

We will use the definition of pH.

pH = -log [H⁺] = -log [H₃O⁺]

[H₃O⁺] = [H⁺] = antilog -pH

[H₃O⁺] = antilog -8.1 = 7.9 × 10⁻⁹ M

Since [H₃O⁺] < 10⁻⁷ M, the solution is basic.

7 0
3 years ago
PH is the a measure of the
wlad13 [49]
PH is the measure of concentration of OH- in the solution
6 0
3 years ago
Read 2 more answers
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