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True [87]
3 years ago
15

You are part of the team to implement new software at XYZ Inc. The employees at XYZ Inc. trust the results of the old software p

rograms, but are cautious about accepting the outcomes of the proposed new software programs. What software implementation strategy would you recommend in this situation?
a. Direct cutover
b. Phase-in approach
c. Pilot startup
d. Parallel start up
Computers and Technology
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

d. Parallel start up

Explanation:

The parallel start-up implementation strategy is the best approach to introducing new software. In this strategy, both systems run simultaneously as the employees gain trust in the new software, and then a complete move can be made over to the new software. A direct cut-over means completely cutting out the old software and moving to a new one, which will not work well in this given scenario. Although the pilot start-up may be cheaper it does not involve all employees but a selected group that will use the new software together with the old one and then after a certain period implement a direct cut-over. The phase-in approach can prove difficult to implement in this scenario, as the software is implemented in phases, throughout the entire company.

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How many bits would be needed to count all of the students in class today? There are 40 students.
Semenov [28]

Answer:

You would need 8 bits.

Explanation:

pls mark brainliest

3 0
3 years ago
Explain the need for data structures when developing software.
Sergio [31]

Solution:

It is  important because, it has to do operation on so without, data structures and algorithms.

It performs these operation:  

 1)Take an input

2) Process it  

3) Give back the output.

The input can be in any form, for ex while searching for directions on google maps,  the starting point and the destination as input to google maps, while logging in to any social sites, We have to give our email and password as input and so on.

Similarly, in the third step, the computer application gives us output in some form or the other.

To make this process efficient, we need to optimize all the three steps.

4 0
3 years ago
Create a new class MyArray_DE and copy and paste the previous program. Be sure to rename the class to MyArray_DE. Modify the pro
vova2212 [387]

Answer:

public class MyArray_DE

{

public static void main(String[] args) {

    int[] numbers = {28, 7, 92, 0, 100, 77};

    int total = 0;

    for (int i=0; i<numbers.length; i++){

        if(numbers[i] % 2 == 0)

            total += numbers[i];

    }

 System.out.println("The sum of even numbers is " + total);

 System.out.println("The numbers in reverse is ");

 for (int i=numbers.length-1; i>=0; i--){

        System.out.print(numbers[i] + " ");

    }

}

}

Explanation:

Since you did not provide the previous code, so I initialized an array named numbers

Initialize the total as 0

Create a for loop that iterates through the numbers

Inside the loop, if the number % 2 is equal to 0 (That means it is an even number), add the number to total (cumulative sum)

When the loop is done, print the total

Create another for loop that iterates through the numbers array and print the numbers in reverse order. Note that to print the numbers in reverse order, start the i from the last index of the array and decrease it until it reaches 0.

4 0
3 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
An engineer has reported that a printer is no longer working and needs troubleshooting. You have been informed that there is a p
gavmur [86]

Answer:

3D Printer.

extruders are in 3D printers.

7 0
2 years ago
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