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KonstantinChe [14]
3 years ago
14

∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′. The c

oordinates of vertex A′ of ∆A′B′C′ are . The coordinates of vertex B′ of ∆A′B′C′ are . The coordinates of vertex C′ of ∆A′B′C′ are .

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

A'(-2, 1), B'(1, 0), C'(-1, 0)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

If a point X(x, y) is translated a units right and b units down, the new location is X'(x + a, y + b) whereas if a point X(x, y) is translated a units left and b units up, the new location is X'(x - a, y - b).

If a point X(x, y) is rotated 90° clockwise about the origin, the new location is X'(y, -x)

From the image attached, ∆ABC is at A(0, 0), B(1,3) C(1, 1)

If ∆ABC is translated 2 units down and 1 unit to the left (x - 1, y - 2), the vertices would be A*(-1, -2), B*(0, 1), C*(0, -1)

If it is then rotated 90° clockwise about the origin, the new location is A'(-2, 1), B'(1, 0), C'(-1, 0)

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Mike watches a caterpillar climbing on a tree trunk. He writes the expression -5/8 - (-1/8 - 1/2) to show the change, in feet, o
Lunna [17]

Answer:

A. \frac{-5}{8}+(\frac{1}{8}+\frac{1}{2})

B. \frac{-5}{8}+(\frac{5}{8})

D. \frac{-5}{8}-(\frac{-1}{8}+(\frac{-1}{2}))

Step-by-step explanation:

- Mike watches a caterpillar climbing on a tree trunk

- He writes the expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2})

- We need to find the equivalent expressions to this expression

A.

∵ The expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2}) has a

   common sign negative in the bracket

∴ \frac{-5}{8}-(-)(\frac{1}{8}+\frac{1}{2})

∵ (-)(-) = (+)

∴ \frac{-5}{8}+(\frac{1}{8}+\frac{1}{2})

∵ The expression \frac{-5}{8}+(\frac{1}{8}+\frac{1}{2}) is

   equivalent to the expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2})

B.

∵ In the expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2}), lets

  add the two terms in the bracket

  (\frac{-1}{8}-\frac{1}{2})=(\frac{-1}{8}-\frac{1(4)}{2(4)})=(\frac{-1}{8}-\frac{4}{8})=(\frac{-5}{8})

∴ The expression = \frac{-5}{8}-(\frac{-5}{8})

∵ (-)(-) = (+)

∴ The expression = \frac{-5}{8}+(\frac{5}{8})

∴ The expression \frac{-5}{8}+(\frac{5}{8}) is equivalent to

   the expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2})

D.

∵ In the expression \frac{-5}{8}-(\frac{-1}{8}-\frac{1}{2}), we can

  write the bracket as (\frac{-1}{8}-\frac{1}{2})=(\frac{-1}{8}+(\frac{-1}{2}))

  because (+)(-) = (-)

∴ The expression \frac{-5}{8}+(\frac{5}{8}) is equivalent to

   the expression \frac{-5}{8}-(\frac{-1}{8}+(\frac{-1}{2}))

* <em>The equivalent expressions are A , B and D</em>

8 0
4 years ago
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