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Akimi4 [234]
3 years ago
5

PLEASE HELP I WILL MARK BRAINLEIST

Mathematics
1 answer:
icang [17]3 years ago
7 0

Answer:

25 mm

Step-by-step explanation:

Set up a proportion where x is the number of millimeters for 160 kilometers

\frac{5}{32} = \frac{x}{160}

Cross multiply and solve for x:

32x = 800

x = 25

So, 25 millimeters represent 160 kilometers

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A family on a trip budgets $1,000 for meals and gasoline. If the price of a meal for the family is $50 and if gasoline costs $3.
galben [10]

Answer:

They can buy 13meals if they buy 100 gallons of gasoline.

Step-by-step explanation:

3.50 PER gallon so 1 gallon is $3.50

if they buy 100 gallons you have to multiply 3.50 by 100 which gives you 350. you subtract 350 from 1000 so 1000-350 and get 650. now, you divide 650 by 50 because each meal is $50. And you get 13 so there you have it.

3 0
3 years ago
Please help asap ill give 5 stars if right and I really need help
Murljashka [212]

Answer:

The scale factor is 3

Step-by-step explanation:

The width of A is 1, the width of B is 3

the length of A is 3, the length of B is 9 so the scale factor from A to B is 3

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3 years ago
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© Given that R= 9x + 8y
Phantasy [73]

Answer:

-19/9

Step-by-step explanation:

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3 years ago
Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn’s
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3 years ago
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

8 0
3 years ago
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