Either way. The probability of hitting the circle is:
P(C)=Area of circle divided by area of square
P(W)=(area of square minus area of circle divided by area of square
P(C)=(πr^2)/s^2
P(W)=(s^2-πr^2)/s^2
...
Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:
P(inside circle)=π/121 (≈0.0259 or 2.6%)
P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
What multiplies to 25 and adds to -10
-5 and -5
(x-5)(x-5)
(x-5)²
3(n-7)=-30
3n-21= -30
3n = -9
n= -3
No.5=1/3x=21
So x is twenty one21
