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natta225 [31]
2 years ago
7

Will give brainliest

Mathematics
1 answer:
telo118 [61]2 years ago
4 0

Answer:

f(x) = x^(1/2) + 3

Step-by-step explanation:

Translating to the right 3 units would change these:

0^(1/2) = 0 /// 3 units to the right would be (0,3)

1^(1/2) = 1 //// 3 units to the right would be (1,4)

4^(1/2) = 2 //// 3 units to the right would be (4,5) etc

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Alice rolls a fair dice and flips a fair coin
NemiM [27]

1,2,3,4,6 are factors of 12

5/6 is the probability of getting a factor of 12

1/2 is the probability of getting a tail

5/6*1/2 = 5 /12

Answer: 5/12

3 0
3 years ago
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What are the vertical angles
wariber [46]
It’s the bottom left answer because the angles are opposite of each other. They are also congruent. I hope this helps!
8 0
3 years ago
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What is the value of log(x exponent 2 y exponent 3 divided by z) when given the following:
Gekata [30.6K]

Answer:

B. 13

Explanation:

\sf\:Given\:expression: log(\dfrac{x^2 y^3}{z} )

Logarithm rules:

\sf (i)  \ \sf log(ab) = log(a) + log(b)\\ \\ (ii) \  log(a/b) = log(a) - log(b)\\\\ (iii) \ log(a^n) = n log(a)

Breakdown of the expression:

\rightarrow \sf log\left(\dfrac{x^2y^3}{z}\right)

\rightarrow \sf log\left(x^2\right) + log\left(y^3\right) - log(z)

\rightarrow \sf 2\log\left(x\right)+3\log \left(y\right)-\log \left(z\right)

insert given values

\rightarrow \sf 2(3)+3(2)-(-1)

\rightarrow \sf 13

7 0
2 years ago
The box plots below show attendance at a local movie theater and high school basketball games:
Firdavs [7]

Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35

From the data, we can say the following:

Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43

Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37

Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.

Answer: D
7 0
3 years ago
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Find the component form of the vector v ⃗ with ‖v ⃗ ‖=4√3 when drawn in standard position v ⃗ lies in Quadrant II and makes a 30
nydimaria [60]
The answer:

first of all, we should know that the expression of a vector V (a, b) can be written as follow:

V = r (Vx i + Vyj), where r is the length of the vector, it is r = sqrt(V²x + V²y)
Vx is the component lying on the x-axis and Vy on the y-axis

<span>v ⃗ lies in Quadrant II, means Vx is less than 0 (negative)
</span>
so Vx= -r sin30° and Vy= rcos30° 

r= <span>‖v ⃗ ‖=4√3 
</span>
so we have   v = - 4√3sin30° i  + 4√3 cos30° j

the components are 

v(- 4√3sin30°,  4√3 cos30°) = (-2√3, 4√3 cos30°)
8 0
4 years ago
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