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zubka84 [21]
2 years ago
12

Solve for y. x + r = yt

Mathematics
2 answers:
astraxan [27]2 years ago
6 0
This is your Answer   y=  x+r​​ / t
                                       






<span>
</span>
34kurt2 years ago
4 0
X+r=yt
divide both sides by t
x+r/t=y
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Keshav has $250 in his account. This is $75 more than his brother Nalin has in his account. Write and solve an addition equation
serious [3.7K]
175 250-75 that would be the answer
5 0
3 years ago
Read 2 more answers
Solve for b.
Dvinal [7]
Expression: <span>a = 9b²c

b</span>² = a/9c

b = √(a/9c)

b = √a/3√c
Or b = 1/3 √(a/c)

In short, Your Answer would be: Option D

Hope this helps!
8 0
2 years ago
Read 2 more answers
Look at this graph:
skad [1K]
<h2>Answer:</h2>

The Slope is \frac{1}{4}\\

<h2>Explanation:</h2>

Notice that both the points, (-7,-6) and (-3,-5), are on the line. So we can use those points to calculate the slope. Recall that that slope of the line m can be calculated by \frac{y_2 -y_1}{x_2 -x_1}\\ if we have the points, (x_1,y_1) and (x_2,y_2).

<h3>Calculating for the slope of the line:</h3>

Given

(-7,-6)

(-3,-5)

m = \frac{-5 -(-6)}{-3 -(-7)} \\ m = \frac{-5 +6}{-3 +7} \\ m = \frac{1}{4}

3 0
3 years ago
Read 2 more answers
Can you solve: 6/5=n+2/2n-3​
OverLord2011 [107]

solving \frac{6}{5}=\frac{n+2}{2n-3} we get value of n: n=4

Step-by-step explanation:

Solving the expression:

\frac{6}{5}=\frac{n+2}{2n-3}

Solving:

\frac{6}{5}=\frac{n+2}{2n-3}\\Cross\,\,multiply:\\6(2n-3)=5(n+2)\\Simplifying:\\12n-18=5n+10\\Combining\,\,like\,\,terms:\\12n-5n=10+18\\7n=28\\n=\frac{28}{7}\\n=4

So, solving \frac{6}{5}=\frac{n+2}{2n-3} we get value of n: n=4

Keywords: Solving Expressions

Learn more about Solving Expressions at:

  • brainly.com/question/1616605
  • brainly.com/question/2586096
  • brainly.com/question/4046256

#learnwithBrainly

4 0
3 years ago
Can you simplify these please thank you
kap26 [50]
-4(9-3)/(8-2) = -4

(8^2-2^5)/(24/6)+3^2= 17

5(16-5)-1/(4^2-7) = 6

Hope this helps! Please rate if I helped you! Any questions please just ask! Thanks!!
7 0
3 years ago
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