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Tatiana [17]
3 years ago
12

Is 50.1 repeating a rational or irrational number?

Mathematics
1 answer:
leonid [27]3 years ago
5 0
Rational numbers can be written as a fraction
can be terminating or repeating decimal (terminating means a decimal that stops ex 5.873) 
so 50.1 repeating is a rational number
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The formula is y2-y1 divided by x2-x1 So now-5+7divided by -2+1 =2/-1= -2
8 0
3 years ago
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Help me PLZZZZ ITSS EASSYYYYYY
vodka [1.7K]

Answer:

The total cost y of a meal.....

Step-by-step explanation:

The total cost of the meal Y suggests addition, which if you added the x and w portions, you would end up with y.

The other answers suggest subtraction, division, or multiplication, which is not being illustrated by the model.

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3 years ago
Aiden has his two friends order a pizza with 12 slices together they ate 2/3 of the pizza if they evenly divided what was left h
IceJOKER [234]

Answer: 1 1/3

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5 0
3 years ago
Use the equation to answer the questions. Round both answers to nearest whole number. Y = 47.25 − 2.25 X If Y equals 8 , what is
noname [10]

Answer:

If Y equals 8, X is equal to 17.

If Y drops to 4, X is equal to 19.

Step-by-step explanation:

We know that the equation is Y = 47.25- 2.25X and we want to find X when Y = 8. To do this we solve the equation for X.

47.25-2.25X=8\\47.25\cdot \:100-2.25X\cdot \:100=8\cdot \:100\\4725-225X=800\\4725-225X-4725=800-4725\\-225X=-3925\\\frac{-225X}{-225}=\frac{-3925}{-225}\\X=\frac{157}{9}=17.4444...

17.4444 rounded to the nearest whole number is 17.

If Y drops to 4,

4 = 47.25- 2.25X\\47.25-2.25X=4\\47.25\cdot \:100-2.25X\cdot \:100=4\cdot \:100\\4725-225X=400\\4725-225X-4725=400-4725\\-225X=-4325\\X=\frac{173}{9}=19.2222...

19.2222 rounded to the nearest whole number is 19.

5 0
4 years ago
The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $⁢1800, which was to be divided equally among t
CaHeK987 [17]
Let's say "p" people were going to the expedition initially, and the cost for each was "c", now, we know the total cost is 1800, so for "p",  folks that'd be  1800/p how much each one cost, namely, how many times "p" goes into 1800.

well, prior to leaving, 15 dropped out, so that leaves us with " p - 15 ", and the cost "c" bumped up to " c + 27 " for each.

\bf \begin{cases}
\cfrac{1800}{p}=\boxed{c}\\\\
\cfrac{1800}{p-15}=c+27\\\\
----------\\
\cfrac{1800}{p-15}=\boxed{\cfrac{1800}{p}}+27
\end{cases}\\\\
-------------------------------\\\\
\cfrac{1800}{p-15}={\cfrac{1800}{p}}+27\impliedby 
\begin{array}{llll}
\textit{let's multiply both sides by}\quad  p(p-15)\\
\textit{to get rid of the denominators}
\end{array}

\bf 1800p=1800(p-15)+27[p(p-15)]
\\\\\\
1800p=1800p-27000+27(p^2-15p)
\\\\\\
0=-27000+27(p^2-15p)\implies 0=-27000+27p^2-405p
\\\\\\
\textit{now, let's take a common factor of }27
\\\\\\
0=p^2-15p-1000\implies 0=(p-40)(p+25)\implies p=
\begin{cases}
\boxed{40}\\
-25
\end{cases}

well, you can't have a negative value of people... so it has to be 40.

so, 40 folks were initially going, then 15 dropped out, how many went on the expedition?  40 - 15.
3 0
4 years ago
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