So the question ask to calculate the over all equation for a certain element and the following are
- over all equation - FE(OH)3+3NH4CI
- over all ionic equation - e(OH)3 (s) & 3 NH4+ (aq) & 3Cl- (aq) - net ionic equation - Fe+3+3OH-+3NH$++3CI-

4 0

3 years ago

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How to spell poop help please

Thepotemich [5.8K]

Answer:

sdadasnj

Explanation:

7 0

2 years ago

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If you added 15,000 calories to 2.0 L of water that was at 25.0 degrees C, what temperature would it be at when you finished?

rewona [7]

Answer:

When we finish, the temperature would be 32.5℃

Explanation:

Density of water = mass/volume

So,

Mass of water = Density × Volume

$\\\\$=1.0 \times 2.0 L$\\\\$=1.0 \frac{g}{m L} \times 2000 m L$\\\\$\quad=2000 g$$

$Q=m \times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0 cal/(g℃))

m is the mass of water

plugging in the values

$15000 \mathrm{Cal}=2000 \mathrm{g} \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times \Delta T$

$\\$\Delta T=\frac{15000 \mathrm{cal}}{2000 \mathrm{g} \times \frac{1.0 \mathrm{cal}}{g^{\circ} \mathrm{C}}}$\\\\$\Delta T=7.5^{\circ} \mathrm{C}$$

Final T = ∆T + Initial T

= 7.5℃ + 25℃ = 32.5℃ (Answer).

5 0

3 years ago

Please help me solve this

Anettt [7]

Answer:

phele to padte nahi phir help magte h

4 0

2 years ago