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Bumek [7]
3 years ago
11

Exactly 313.5 J will raise the temperature of 10.0 g of a metal from 25.0 C to 60.0 C. What is the specific heat of the metal?

Chemistry
1 answer:
torisob [31]3 years ago
4 0
From the equation Q = m\cdot c_e\cdot \Delta T we can clear specific heat:

c_e = \frac{Q}{m\cdot \Delta T}\ \to\ c_e = \frac{313.5\ J}{10\ g\cdot (60 - 25)^\circ C} = \bf 0.896\frac{J}{g\cdot ^\circ C}
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2 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
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3.43×10¹ mol

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The number of moles and volume are directly proportional to each other at same temperature and pressure.

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